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BlackZzzverrR [31]
3 years ago
12

Is (9,5) a solution to this system of inequalities?

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

yes it is..............

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Solve for x 5x2-4x=6
Harlamova29_29 [7]

Answer:

That would equal 36

Step-by-step explanation:

i added them up

8 0
3 years ago
Wo commondities A and B cost 070 and D80 respe
Mariana [72]

Answer:

b) 65.08

ii) 0.75

Step-by-step explanation:

x(Kg):                  62      63     64     65     66     67     68

Frequency(f):      1          5        11       15      10     6        2

           xf:           62       315    704    975  660  402    136

b) mean(X) = ∑xf/N = 3254/50 = 65.08

c) x - X :          -3.08    -2.08    -1.08    -0.08        0.92   1.92    2.92

   (x - X)²:        9.49     4.33      1.17       0.0064    0.85   3.69    8.53

ii) Standard deviation(S.D.):  √(∑(x - X)²/N = √(28.0664)/50 = √0.5613

 ∴ S.D.= 0.75

8 0
3 years ago
(Level 4) In a bag of orange, red, and yellow, 60% are orange, and 10% are red. There
Serhud [2]

The answer is 22 orange marbles. Let me explain. Since 60% are orange and 10% are red, the rest, 30% is yellow. So we learn that every 10% equals to 2 marbles. If you add 60% + 50% = 110%

90% = 18

And we have to add 4 more because 10%×2.

So the total comes to 18+4= 22.

3 0
3 years ago
What is the slope of a line perpendicular to a line with slope -8 ?
Alexandra [31]

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-8\implies \cfrac{-8}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{-8}}\qquad \stackrel{negative~reciprocal}{\cfrac{1}{8}}}

4 0
3 years ago
Read 2 more answers
You measure 22 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.
lara31 [8.8K]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the true population mean textbook weight.

Number of sample, n = 22

Mean, u = 64 ounces

Standard deviation, s = 5.1 ounces

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

64 ± 1.645 × 5.1/√22

= 64 ± 1.645 × 1.087

= 64 ± 1.788

The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces

The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces

Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces

3 0
3 years ago
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