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Elan Coil [88]
3 years ago
5

When performing the ipconfig command, what does the following output line depict if found in the tunnel adapter settings?

Computers and Technology
1 answer:
Andrew [12]3 years ago
8 0

Answer:

d. IPv4 Address 192.168.0.4 is associated with the globe IPv6 address 2001:db8:0:10:0:efe

Explanation:

The adapter setting will be associated with the global IP address. When Ipconfig command is operate the IP address finds the relevant domain and then address will use a different subnet. The network will use both IPv4 and IPv6 subnets in order to execute the command.

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adell [148]

An excel user should use a relative cell reference when it is important to preserve the relationship to the formula location. When you create a formula that references other cells, excel does not normally "record" the exact cell address. Instead, it looks at the at the relationship that cell has to the other cell containing the formula.

7 0
3 years ago
Please I need help.
fredd [130]

Answer:

The answer is the "TO address"

Explanation:

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4 0
3 years ago
What is the value of 8n when n= = 2?​
lidiya [134]

Answer:

The value of 8n would be 16

8n

8(2)= 16

(uhh this is a math question right? Sorry if it has to deal with tech)

6 0
3 years ago
Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
Look at the following assignment statements:
ziro4ka [17]

Answer: number 2 is the correct way to do it

Explanation:

3 0
3 years ago
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