Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The value stored by a variable can be changed after it is assigned(true).
The value of a variable can be changed after it is assigned, for example:
int a=10;
and we can change the value of variable a in letter program such as:
a=15;
Variables are a name for a spot in the computer's memory (true).
it is true, because the variables value stored in the computer's memory and we can access theses values by their name (variable name). so Variables are a name for a spot in the computer's memory.
Variable names can be words: such as temperature or height (true).
Yes, the variable name can be words such as height, width, temperature etc.
The value stored by a variable cannot be changed after it is assigned (false).
It is noted that the value stored by a variable can be changed after it is assigned. However, it is noted that is some programming language, you can't change the value of static variable.
Answer:
True hope this helps you and everyone!
1.) narrative = a THATS all I can answer rn sorryyyy
