This can be solved by Newton's binomial formula
Tk+1 = (n k) a∧(n-k) b∧k k+1=7 => k=6, n=11 , a=-3x and b=-2y
T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6
T7= 462 (-3x)∧5 (-2y)∧6
The correct answer is A.
Good luck!!!
Answer:
He can drive 481 miles if David rents his car for three days
Step-by-step explanation:
This is true because if you take the 24.95 and multiply it by 3, because he rented it for three days, you'll get 74.85. Then you'll subtract 200 (the total money that can be spent) by 74.85 you'll get 125.15. Divide the remaining number, 125.15 by 0.26 to get 481.34. Take the decimals away because you don't need it, if you want to be sure it's correct you can multiply 481 by 0.26 to get 125.05 which is lower than 125.15 so it good because if you use 482 besides 481 it will be higher than the amount of money David can spend, that's why 481 is the right answer.
Answer:
= 64 - 4 =60
Step-by-step explanation:
Answer:
- registration fee: $50
- monthly fee: $80
Step-by-step explanation:
Let r and m represent the registration fee and the monthly fee, respectively. We are told that the charges are ...
370 = r + 4m
530 = r + 6m
This is your system of equations.
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Subtract the first equation from the second to start the solution.
(530) -(370) = (r +6m) -(r +4m)
160 = 2m . . . . . . simplify
80 = m . . . . . . . . divide by 2
Using this value in the first equation, we find ...
370 = r + 4(80)
50 = r . . . . . . . . . . . . subtract 320
The registration fee is $50; the monthly fee is $80.
Answer:
week 12
Step-by-step explanation:
not sure if i can read it correctly but it looks like she gets below 120 after 12 lines. plus 130-12 is less than 120
