Can someone help me with “Write The Following In Standard Form?” This is due in a few minutes please help!

Mathematics

1 answer:

Volgvan3 years ago

5 0

Answer:

Step-by-step explanation:

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HELP ASAP PLZ IM TIMED

nasty-shy [4]

Answer:

Step-by-step explanation:

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2 years ago

HELLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

MrRa [10]

Answer:

Step-by-step explanation:

you have to find the answer to 8t by the power of 2 multiplied witch is 64 + 32t = 96

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2 years ago

Max wakes up at 7:00am. It take him 10 minutes to get dressed, and 5 minutes to eat breakfast. The bus will pick up max at 7:40a

irinina [24]

Note: I will be using the information in your attachment to answer the question.
Add the minutes to the initial time: 7:00 + 10 minutes + 7 minutes + 5 minutes = 7:22
He will be ready to board the bus at 7:22.
Subtract this time from the time the bus is schedule to pick him up: 7:40 - 7:22 = 18
Max will have 18 minutes before the bus picks him up.

3 0

3 years ago

Confusedddddddddddddddd

Elina [12.6K]

4x + 4 + 4x = 180 so solve for x and it’s 22
1. 4x + 4
92

2. 88

4 0

3 years ago

A+2/a-5÷a+1/a2-8a+15

krok68 [10]

For $A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15$

Combine the fractions $\frac{2}{a} - \frac{5}{a} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{2-5}{a}$

$\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \ \frac{-3}{a}$

$\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \ -\frac{3}{a}$

Therefore our final answer is $A-\frac{3}{a}+\frac{1}{a^2}-8a+15$

Hope this helps!

3 0

3 years ago