Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).
Subtract 160 from both sides.
Divide by –20, we get
f = 2.50
Substitute f = 2.5 in equation (3), we get
b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Answer:
k = 4
Step-by-step explanation:
f(x)=5x+k
Let x =2
f(2) = 5*2 +k
f(2) = 10+k
We know f(2) = 14
14 = 10+k
Subtract 10 from each side
14-10 = 10+k-10
4 =k
Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
I'm pretty sure its 100 because if she gave each of her 19 students 5 invitations that equals 95. (19×5=95) And She had 5 leftover equals 100. (95+5=100)
Sorry that’s it’s sloppy i tried to write it on my phone. hope this part helps. i’ll try to do the bottom part now
