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horrorfan [7]
3 years ago
12

2/5, -1/6, -11/30ASAP​

Mathematics
1 answer:
Doss [256]3 years ago
6 0

Answer:

your qiestion is not clear.

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I will give the BRAINIEST!!!<br><br>Which of these statements best describes the relation shown? ​
ludmilkaskok [199]

Answer:

i believe the answer is C

Step-by-step explanation:

i dont know its just what i would choose im not the smartests in math

3 0
3 years ago
Help meeee with this questionnnnnnnnnn!!!!!!!!!!!!
Dafna1 [17]

Given:

The scale factor between two circles is \dfrac{2x}{5y}.

To find:

The ratio of their areas.

Solution:

We know that, all circles are similar.

The ratio of the areas of similar figures is equal to the ratio of squares of their corresponding sides or equal to the square of ratio of their corresponding sides.

The scale factor is the ratio of the corresponding sides.

Ratio of areas of circles = Square of scale factor between two circles

\text{Ratio of areas of circles}=\left(\dfrac{2x}{5y}\right)^2

\text{Ratio of areas of circles}=\dfrac{(2x)^2}{(5y)^2}

\text{Ratio of areas of circles}=\dfrac{4x^2}{25y^2}

Therefore, the correct option is D.

3 0
3 years ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

5 0
3 years ago
A bean plant grows at a constant rate for a month. After 10 days, the plant is
Rzqust [24]

The height of plant y =x+25

7 0
3 years ago
Need help on this becOuse I don't understand
joja [24]
Six pounds of rice is $18 homie

8 0
4 years ago
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