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sp2606 [1]
3 years ago
7

A number that, when multiplied with another number, yields a result of 1 is called its multiplicative ____.

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

Answer:

inverse

Step-by-step explanation:

Aliun [14]3 years ago
5 0

Answer:

multiplicative inverse

Step-by-step explanation:

A number that is multiplied by it's multiplicative inverse equals one.

A multiplicative inverse is also called a reciprocal.

Example:

1/7 is 7's multiplicative inverse.

\frac{7}{1} *\frac{1}{7} =\frac{7}{7} =1

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If f(x) = x-6 and g(x) = x^1/2 , find g(x) x f(x) .
shusha [124]

Answer:

x^3/2 - 6x^1/2

Step-by-step explanation:

f(x) = x - 6

g(x) = x^1/2

g(x) * f(x) = x^1/2(x - 6)

g(x) * f(x) = x^3/2 - 6x^1/2

5 0
3 years ago
Help me with this plzzzz
Firlakuza [10]

Answer:

0.25 or 1/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
A bag contains white marbles and green marbles, 108 in total. The number of white marbles is 6 more than 5
sweet-ann [11.9K]

27.6

108/5= 21.6+6= 27.6

3 0
3 years ago
If 1 is subtracted from the numerator and from
max2010maxim [7]
1 - 2/3 = 1/3


1+ (-1/3) = 2/3

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