1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marat540 [252]
3 years ago
14

Please please help ASAP please please I’ll mark you as a branlist

Mathematics
1 answer:
wel3 years ago
5 0

Answer:

4°

Step-by-step explanation:

Since it is said that the angles are corresponding angles so we know that corresponding angles are equal then,

<1 = <2

3x - 7 ° = x - 1°

3x - x = 7° - 1°

2x = 8°

x = 8° / 2

Therefore x = 4°

Hope it will help you :)

You might be interested in
Craig went bowling with $25 to spend he rented shoes for $5.25 and paid $4dollars for each game what was the greatest number of
BlackZzzverrR [31]
He would play 4 games.
3 0
3 years ago
Read 2 more answers
VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
Zepler [3.9K]

C. Reflected over the y-axis and translated up 1 unit

3 0
3 years ago
Read 2 more answers
A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon
algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_{men} \leq \mu_{women}

Alternative hypothesis:\mu_{men} > \mu_{women}

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_{calc}

Since is a right tailed test test the p value would be:

p_v =P(Z>z_{calc})=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0
3 years ago
WWhat is the value of p2+p+10 when p=4​
Reptile [31]

Answer:

value = 30(thirty).....

7 0
2 years ago
I traveled 117 miles in 2.25 hours. What was my average speed? How would I solve this ?
LenKa [72]
117 miles in 2.25 hours

Divide both numbers by 2.25

52 miles per hour

3 0
2 years ago
Read 2 more answers
Other questions:
  • Goven the graphs of h(x) and k(x) find:
    7·2 answers
  • The same honey is sold in two different size jars , large jar - 540g for £4.10 small jar-360g for £2.81 , by considering the amo
    6·1 answer
  • Please help me out. :)
    11·1 answer
  • 100 points PLEASE HELP!!!
    10·1 answer
  • Mr. Thomas deposited 2500 in a new bank account. The bank pays 6.5% interest compounded annually on this account. He makes no de
    12·1 answer
  • A. a relation only
    7·2 answers
  • Two angles that are directly across from each other when two lines intersect. supplementary angles complementary angles adjacent
    6·2 answers
  • NOT GRADED. <br>FIND THE MEASURE OF THE INDICATED ANGLE IN EACH TRIANGLE.​
    6·2 answers
  • Jane had $60. She spent an average of $5 each day. How many days did
    11·1 answer
  • A flower vase bought for Rs. 72 and sold for Rs. 63. Find the loss percent.​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!