2 years ago

I need help on this problem

Mathematics

1 answer:

AlladinOne [14]2 years ago

4 0

Answer:

y² - 2y - 4x + 9 = 0 (*)

a = 1 b = -2 c = -4x + 9

Δ = b² - 4ac = 4 - 4(9 - 4x) = 4 - 36 + 16x = 16x - 32

if (*) have the solutions => Δ ≥ 0

⇔ 16x - 32 ≥ 0 ⇔ x ≥ 2

with x ≥ 2 => y = $\frac{2+\sqrt{16x-32} }{2}=\frac{2+4\sqrt{x-2} }{2}=1+2\sqrt{x-2}$

or y = $1-2\sqrt{x-2}$

Step-by-step explanation:

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