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cestrela7 [59]
3 years ago
15

I need help on this problem ​

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

y² - 2y - 4x + 9 = 0 (*)

a = 1    b = -2    c = -4x + 9

Δ = b² - 4ac = 4 - 4(9 - 4x) = 4 - 36 + 16x = 16x - 32

if (*) have the solutions => Δ ≥ 0

⇔ 16x - 32 ≥ 0 ⇔ x ≥ 2

with x ≥ 2 => y = \frac{2+\sqrt{16x-32} }{2}=\frac{2+4\sqrt{x-2} }{2}=1+2\sqrt{x-2}

or y = 1-2\sqrt{x-2}

Step-by-step explanation:

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ivann1987 [24]
Random numbers from 0-9 with 0, 1, 2, and 3 being rain and 4, 5, 6, 7, and 8 being cloudy.

7 0
3 years ago
Convert y + 3 = -3(x + 5) to standard form.
emmasim [6.3K]
Hi there!

y  + 3 =  - 3(x + 5)
First we need to work out the parenthesis, which can for instance be done using rainbow technique.

y + 3 =  - 3x  -  15
Now subtract 3 from both sides.

y =  - 3x  - 18
And finally add 3x to both sides.

3x + y =  - 18
The 4th answer choice is correct.



6 0
3 years ago
16- X = -2<br> Solve for x
Licemer1 [7]

Answer: x=18

Step-by-step explanation: 16-18=-2

Good luck! :)

7 0
3 years ago
Read 2 more answers
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
2 years ago
What is 36.993 to the nearest thousandth
finlep [7]

The next larger thousandth is 36.994 .
The next smaller thousandth is  36.992 .
Neither of those is any nearer to  36.993
than  36.993  already is.

The last '3' at the end of 36.993 is in the thousandths' place.
There is no more piece of another thousandth after it.
So  36.993 is already on a complete thousandth, and
there's no rounding required.

7 0
3 years ago
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