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cestrela7 [59]
3 years ago
15

I need help on this problem ​

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

y² - 2y - 4x + 9 = 0 (*)

a = 1    b = -2    c = -4x + 9

Δ = b² - 4ac = 4 - 4(9 - 4x) = 4 - 36 + 16x = 16x - 32

if (*) have the solutions => Δ ≥ 0

⇔ 16x - 32 ≥ 0 ⇔ x ≥ 2

with x ≥ 2 => y = \frac{2+\sqrt{16x-32} }{2}=\frac{2+4\sqrt{x-2} }{2}=1+2\sqrt{x-2}

or y = 1-2\sqrt{x-2}

Step-by-step explanation:

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35 out of the 50 employees at the sports shop are part-time employees. What percentage of the employees at the sports shop work
ANTONII [103]

Answer:

70% Employee at the sports shop work part time.

Step-by-step explanation:

<u>Given Data:</u>

Total Employees = 50

Part-Time Employees = 35

<u>Formula:</u>

Percentage of Part-Time Employees =

(Part-Time Employees/Total Employees) x 100

=(35 / 50) x 100

=(0.7) x 100

= 70

so

The Percentage of Part-Time Employees is 70%.

3 0
2 years ago
I have a lot of questions to ask on mathematics...<br>so pls help so fast<br>thnx a lot...​
melomori [17]

Answer:

WHAT DO YOU need help with

8 0
3 years ago
Which numbers belong to the domain of the relation?Choose all answers that are correct.
STALIN [3.7K]
B and D because the domain is the set of X coordinates. (x, y) x is your domain.
6 0
3 years ago
Translate the sentence into an equation. Four times the difference of a number and 5 is 24.
givi [52]
4\ times\to4\times\\difference\ of\ a\ number\ "c"\ and\ 5\to c-5\\is\ equal\ 24\to=24\\\\4\times(c-5)=24\\\\Answer:\boxed{a.}
3 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
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