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inna [77]
2 years ago
13

This isnt a question im just saying that you all shouldn't vape!!

Mathematics
2 answers:
velikii [3]2 years ago
8 0

Answer:

i agree

Step-by-step explanation:

vape bad no good

Ksju [112]2 years ago
3 0

Answer:

ok soooooooooo9oooooooooooooooooooo

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6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0
2 years ago
Need help solving this question please.
jok3333 [9.3K]

Answer: b) they loaded 112356 lbs of cargo

Step-by-step explanation:

When a boat or an object floats in water, the volume of water that it displaces is equivalent to its weight.

When moving into the port, the cargo boat displaced 2200 ft³ of water. Since the density of water is 62.42 lb/ft³ and mass = density × volume, then the mass of the cargo boat on entering the port is

2200 × 62.42 = 137324 lbs

On leaving the port, it displaces 4000 ft³ of water. The mass of the cargo boat on leaving the port is

4000 × 62.42 = 249680 lbs

The difference in both masses is

249680 - 137324 = 112356 lbs

Therefore, they loaded 112356 lbs of cargo

4 0
3 years ago
The equation of the graph line is 2X-3Y=12
Klio2033 [76]

Answer:

A. -4

Step-by-step explanation:

For solving for x intercepts analytically. You can set the the y in the equation to 0. So, 2x-3(0)=12, and solving for x will get you -4.

You can also solve graphically by plugging in the equation and looking at where it intercepts the x axis.

3 0
3 years ago
Read 2 more answers
Help Pls if you want!!!!
Tom [10]

Answer:

Its 2.5 percent ladd enjoy

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
Alecsey [184]

For this case we must indicate which of the equations shown can be solved using the quadratic formula.

By definition, the quadratic formula is applied to equations of the second degree, of the form:

ax ^ 2+ bx+ c = 0

Option A:

2x ^ 2-3x +10 = 2x + 21

Rewriting we have:

2x ^ 2-3x-2x+ 10-21 = 0\\2x ^ 2-5x-11 = 0

This equation can be solved using the quadratic formula

Option B:

2x ^ 2-6x-7 = 2x ^ 2

Rewriting we have:

2x ^ 2-2x ^ 2-6x-7 = 0\\-6x-7 = 0

It can not be solved with the quadratic formula.

Option C:

5x ^ 2 + 2x-4 = 2x ^ 2

Rewriting we have:

5x ^ 2-2x ^ 2 + 2x-4 = 0\\3x ^ 2 + 2x-4 = 0

This equation can be solved using the quadratic formula

Option D:

5x ^ 3-3x + 10 = 2x ^ 2

Rewriting we have:

5x ^ 3-2x ^ 2-3x + 10 = 0

It can not be solved with the quadratic formula.

Answer:

A and C

4 0
3 years ago
Read 2 more answers
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