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3 years ago

Please help me out! the question is

Mathematics

1 answer:

kupik [55]3 years ago

5 0

They had the same quotient because both of those equations are equal

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Regina’s teacher recently gave her a homework assignment on solving equations. Since she has been thinking about saving for a ne

creativ13 [48]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

Hi piiihvvyjcycycfvyfchchv cgcydyfcyv fyiyifycgxt4w67 ftuddtyxd

Nataly_w [17]

Hello person above

How are you?

5 0

3 years ago

Explain how to find a measure of angle ACD <br> without repositioning the protractor

MatroZZZ [7]

Answer:

60 degrees

Step-by-step explanation:

ACD and ACB are complementary angles. Find ACB=30 degrees. Subtract 30 from 90 degrees. ACD=60 degrees.

6 0

3 years ago

Given that

timofeeve [1]

Answer:

Step-by-step explanation:

(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α

But sec^2 α = 1 + tan^2 α so

sec^2 α - tan^2α = 1 + tan^2 α - tan^2α

= 1

so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α

1/4 * x = 1

x = 4.

6 0

3 years ago