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qwelly [4]
3 years ago
5

Please help me out! the question is

Mathematics
1 answer:
kupik [55]3 years ago
5 0
They had the same quotient because both of those equations are equal
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16. Hamster Heaven charges an annual fee of $20 plus $2.50 for each day of hamster
Ludmilka [50]

Answer:

hamster heaven

y=20+2.5x

hamster fun world

y=35+x

Step-by-step explanation:

by solving we get

x=10

y=45

by comparing the graph hamster fun world 8s cheaper on the long run

Mark Me Brainliest

8 0
2 years ago
1) (6x2 + 14 - x) + (2x - 2 - 4x2)
lakkis [162]
1 is 1
2 is going to be -8x to the second minus 6 x
3 is 3 plus three x two minus seven x plus two xx 2 minus 6xto the 2
4 is 11
3 0
2 years ago
#4 need help with this one
4vir4ik [10]

Answer:

x = 25.6

Step-by-step explanation:

As we can see, this is a right triangle, so there are known relationships

well to start we have to know the relationship between angles, legs and the hypotenuse

α = 43

a: adjacent  = x

o: opposite

h: hypotenuse  = 35

sin α = o/h

cos α = a/h

tan α = o/a

we see that it has (angle, adjacent, hypotenuse)

cos α = a/h

cos 43° = x / 35

cos 43° * 35 = x

25.59 = x

if we want to round to the nearest tenth

x = 25.59 = 25.6

4 0
3 years ago
Read 2 more answers
Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.
kap26 [50]

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

Area=\pi r^2/2

Area=\pi (3)^2/2=9\pi /2

The area of a rectangle is the length multiplied by the width:

Area=l*w

Area=6*9=54

The net area is the sum of the rectangle and the semi-circle:

Area=(9\pi /2)+(54)=68.1

8 0
2 years ago
3) -5
xxMikexx [17]

Answer:

Constant monomial

Step-by-step explanation:

Monomial means that there is only one term, so constant trinomial cannot be correct.

Quintic monomials have a degree of 5 and quadratic monomials have a degree of 4, but this has a degree of zero, so this must be a constant monomial.

I hope this helps you. Have a nice day.

8 0
3 years ago
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