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AnnZ [28]
3 years ago
6

27 is 76% of what number?

Mathematics
2 answers:
DanielleElmas [232]3 years ago
5 0

Answer:

36

Step-by-step explanation:

i think im right about this

Ainat [17]3 years ago
3 0

Answer:

35.53

Step-by-step explanation:

100% of 35.53 is 35.53 so 76% of 35.53 is 27

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Lance rides his bike at a constant speed of 32 mph. Write an equation to represent the total distance, d, he can ride in h hours
wolverine [178]

Answer:

d = 32h

Step-by-step explanation:

5 0
3 years ago
Twenty four over the quantity of 3 x minus two. Find f(−2).
TEA [102]
Answer:

f(-2) = -3

Explanation:

Not sure if those last couple numbers are answer choices, but I'm going to infer that they might be.

Twenty four over the quantity of 3 x minus two in standard form is:

f(x) = <span>24<span>3x−2</span></span>

Since the number in the ( ) = x, plug in for x using f(-2)

<span>24<span>3∗<span>(−2)</span>−2</span></span>

P E {M D} {A S} for where to solve first

Multiply the 3 and (-2):

<span>24<span>−6−2</span></span>

Add -6 and -2:

<span>24<span>−8</span></span>

Divide the rest:

f(-2) = -3

3 0
3 years ago
Arpitha lined up the interior angles of the triangle along the line below. Triangle A B C. Angle C is 99 degrees. 2 lines extend
uysha [10]

Answer:

B

Step-by-step explanation:

Because i took the test

8 0
3 years ago
Read 2 more answers
Antonio is going to the carnival. He can spend no more than $20.00. if the ticket to in is $7.50, and each ride cost $1.25, how
fgiga [73]
$20.00 ≥ 7.50+1.25x
subtract 7.50 from both sides
20-7.50=12.50
12.50=1.25x
12.50/1.25=10
x= 10 rides
6 0
3 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
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