Which sequence is geometric?

Mathematics

1 answer:

bija089 [108]3 years ago

3 0

Answer:

4th option

Step-by-step explanation:

in geometric sequences the number is multiplied or divided by same number continuously

in the 4th option we can see that the number 1 is multiplied by 4 continuously so the correct answer would be that.

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Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

The chlorine per liter of water in the pool is 2.5 milligrams.

The volume of water in the swimming pool is 8000 gallons.

Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be $x.$

The gallons of water in the swimming pool = 8000.

The milligrams of chlorine per liter of water in the pool = 2.5.

According to question, the amount of chlorine in the swimming pool is proportional to the volume of water.

So, 2.5 mg of chlorine is equivalent to 1 liter.

Thus, $x$ is equivalent to $8000.$

Now, to get the quantity of chlorine by using cross multiplication method:

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<em>By cross multiplying we get:</em>

$20000=x\\\\x=20,000\ mg.$

Therefore, there are 20,000 milligram chlorine in the pool.

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3 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.