Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
Option C is correct
Step-by-step explanation:
We need to factorize the expression:
For factorization we need to break the middle term such that the product is equal to 24x^2 and the sum is equal to 10x
We know that 6*4 = 24 and 6+4 =10
So, solving
Taking common
So, the factors of
are
Hence Option C is correct
Answer:4
Step-by-step explanation: this but u can use.kkk p h o t o m a t h
Well, $107 times 7 is $749, is that what ypu needed?
Answer:
Coordinates of C are (a,a)
Step-by-step explanation:
As x-coordinate of C is equal to that of coordinate D (a)
y-coordinate of C is equal to that of coordinate B (a)
So,
Coordinates of C are (a,a)
i hope it will help you!
