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lawyer [7]
2 years ago
5

(b) The area of a rectangular pool is 5488 m\2 If the length of the pool is 98 m, what is its width?​

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
7 0

Answer:

56

Step-by-step explanation:

To find the area of a rectangle we have the foruma A=WxL.

But we already have the area and length so we can plug that in

5488=Wx98

Now its an algebreic expression.

SInce its multiplying we do the opposite, so we divide 98 on both sides.

98/98 crosses itself out so now its 5488/98. Which equals 56. So now our expression is W=56. To fact check we put the numbers 56 and 98 into the formula to see if we get 5488.

A=56x98

A=5488

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Can anyone find the answer????
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What are the zeros of the quadratic function f(x) = 6x^2 + 12x - 7?
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4 0
3 years ago
29. Which of the following expressions will result in a real answer after being simplified? Select all that apply.
nexus9112 [7]

Answer: A, B, C, and E

Step-by-step explanation:

If both sides are real numbers, then the product will be a real number.

If in at least one of the sides we have a complex number, then the product will be real if:

The other number is zero.

The other number is the conjugate of the first.

This is when:

Suppose we have a number:

z = a + b*i

The conjugate will be:

w = a - b*i

And the product between them is:

(a + b*i)*(a - b*i) = a^2 + a*b*i - a*b*i + b^2 = a^2 + b^2

Then the options that will have a real answer are:

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Walter is practicing his high jumps for the track team. His first jump measured 5 feet, 9 inches. His second jump measured 3 fee
tia_tia [17]

Answer: 1.834 ft

Step-by-step explanation:

Given

Walter's first Jump is 5 ft, 9 in.

His second Jump is 3 ft, 11 in.

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1\ ft=12\ in

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The difference in the measurement of two Jumps is

\Rightarrow 5.75-3.916=1.834\ ft

So, Walter first Jump is 1.834 ft higher than the second Jump

3 0
3 years ago
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