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Nikolay [14]
3 years ago
12

Figure B is the image of Figure A when reflected across line 1. Are

Mathematics
2 answers:
Komok [63]3 years ago
7 0

Yes, Figure A. and Figure B. are congruent. The definition of congruent is identical in form; coinciding exactly when superimposed. And if they are reflected it means, they are identical.

OLEGan [10]3 years ago
6 0

Answer:

There just reflected so its the same

Step-by-step explanation:

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Is​ f(x) continuous at x equals 4​? Why or why​ not? A. ​No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit
soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0
3 years ago
mplete the work to solve for y: 2 5 ( 1 2 y + 5 ) − 4 5 = 1 2 y − 1 + 1 10 y 1.Distributive property: 1 5 y + 2 − 4 5 = 1 2 y −
Wewaii [24]

Answer: 104 I think

Step-by-step explanation:

7 0
3 years ago
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creativ13 [48]

Answer:

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Step-by-step explanation:

3 0
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Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). Tiles f(x) = x2 − 9, and
vitfil [10]
For this case we must solve each of the functions.
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4 0
3 years ago
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Which expression represents the difference between 2n and 15
ValentinkaMS [17]
Is these the choices to chose from:
<span>A) 2n-15
B) 15-2n
C) Both A and B
D) Neither A nor B

*If so, i think its C*</span>
4 0
3 years ago
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