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3 years ago

12

Figure B is the image of Figure A when reflected across line 1. Are

2 answers:

Komok [63]3 years ago

7 0

Yes, Figure A. and Figure B. are congruent. The definition of congruent is identical in form; coinciding exactly when superimposed. And if they are reflected it means, they are identical.

OLEGan [10]3 years ago

6 0

Answer:

There just reflected so its the same

Step-by-step explanation:

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Solve by completing the square. Round your answers to the nearest tenth and then locate the greater solution. <img src="https://

Andrews [41]

Step-by-step explanation:

Step 1: Write our Givens

${x}^{2} + 10x - 7 = 0$

Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

${x}^{2} + 10x = 7$

Next, we take the linear coeffeicent and divide it by 2 then square it.

$( \frac{10}{2} ) {}^{2} = 25$

Then we add that to both sides

${x}^{2} + 10x + 25 = 7 + 25$

${ {x}^{2} } + 10x + 25 = 32$

Next, we factor the left,

$(x + 5)(x + 5) = 32$

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

$(x + 5) {}^{2} = 32$

This is called a perfect square trinomial.

Next, we take the square root of both sides

$x + 5 = ± \sqrt{32}$

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

$x = - 5± \sqrt{32}$

The greater solution is when sqr root of 32 is positive so the answer to that is

$\sqrt{32} - 5 = 0.7$

3 0

2 years ago

Suppose that LMN is isosceles with base LN suppose that M

ira [324]

Given:

In an isosceles triangle LMN, LM=MN.

$m\angle M=(3x+17)^\circ,m\angle L=(2x+36)^\circ$

To find:

The measure of the angles L, M and N.

Solution:

In triangle LMN,

$LM=MN$ (Given)

$m\angle N=m\angle L=(2x+36)^\circ$ (Base angles of an isosceles triangle are equal)

Now,

$m\angle L+m\angle M+m\angle N=180^\circ$

$(2x+36)^\circ+(3x+17)^\circ+(2x+36)^\circ=180^\circ$

$(7x+89)^\circ=180^\circ$

$(7x+89)=180$

On further simplification, we get

$7x=180-89$

$7x=91$

$x=\dfrac{91}{7}$

$x=13$

The value of x is 13. Using this value, we get

$m\angle L=(2(13)+36)^\circ$

$m\angle L=(26+36)^\circ$

$m\angle L=62^\circ$

Similarly,

$m\angle M=(3(13)+17)^\circ$

$m\angle M=(39+17)^\circ$

$m\angle M=56^\circ$

And,

$m\angle N=m\angle L$

$m\angle N=62^\circ$

Therefore, the measure of angles are $m\angle L=62^\circ,m\angle M=56^\circ,m\angle N=62^\circ$ .

5 0

3 years ago

How to solve -2x+y =-10

cestrela7 [59]

You can't solve this unless you have numbers to substitute or another equation.

5 0

3 years ago

Read 2 more answers

How to identify the domain and range of a function?

sergiy2304 [10]

Domain are the values of x, range are the values of y

3 0

3 years ago

2. State two (2) values of θ (theta) to the nearest degree for<br> sin θ = − 0. 966

emmasim [6.3K]

Using equivalent angles, the solutions to the equation are given as follows:

$\theta = 255^\circ, \theta = 285^\circ$

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the equation is:

$\sin{\theta} = -0.966$

Applying the inverse relation:

$\theta = \arcsin{-0.966} = 255^\circ$

Which is on the third quadrant. The equivalent angle on the fourth quadrant is given as follows:

$270^\circ + (270^\circ - 255^\circ) = 285^\circ$

More can be learned about equivalent angles at brainly.com/question/28025397

#SPJ1

5 0

2 years ago