1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrRissso [65]
3 years ago
13

Find the GCF for 40 and 48 *

Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

8

Step-by-step explanation:

You might be interested in
What is standard form for 6.43999001 x 10^8
Romashka [77]
6.43999001  
1st  you move the decimal 8 times to your right 
once you are done moving the decimal you should end up with a whole number 
you answer is (643, 999, 001)
5 0
2 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Makovka662 [10]
The answer is 26.19. It’s 100% right.
4 0
2 years ago
Write an equation that represents"Four less than the difference of half a number and 3 is 20 ."Use X for the variable.​
Alex73 [517]

Answer:

{(1/2)x-3}-4=20

That is your answer.

8 0
3 years ago
What is 6 plus 12 times 8-3
9966 [12]

Answer:

99

Step-by-step explanation: Use PEMDAS

12+8 = 96

96+6 = 102

102-3 = 96

Hope this helped!

4 0
3 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
2 years ago
Other questions:
  • *question 2*<br> I NEED HELP ASAPPPP
    12·1 answer
  • Which country had control of Mali?<br><br>Italy<br>Great Britain<br>Spain<br>France
    11·1 answer
  • Given the function f(x) = 2x, find the value of f−1(16).
    7·2 answers
  • At CVS, a pack of batteries cost $8.34. Orlando has only $3.00. How many batteries can he buy? How much money will he have left?
    5·1 answer
  • Simplify the following expression:
    14·1 answer
  • Please help due in 5 minutes I know its a long question but I will give brainliest.
    15·2 answers
  • Help please ASAP TY :)
    8·2 answers
  • Geometry help don’t take points if I get 70%+ I’ll give some away!!
    14·1 answer
  • Question is in the photo!
    9·2 answers
  • Roxanne likes to fish. She estimates that 30% of the fish she catches are
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!