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sergeinik [125]
3 years ago
8

CAN SOMEONE PLEASE HELP ME. I NEED HELP ON THIS QUESTION​

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

a segment cd only

Step-by-step explanation:

segment cd is the only line that passes through segment ab at a right angle

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A solution of the equation 3x + y = 15?
Tamiku [17]

Step-by-step explanation:

Since there is 2 unknown variable ,

so we need 2 equation to find their values.

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1 year ago
The measure of angle 1 is 65 degrees. What are the measures of the other seven angles? (Enter the
Anika [276]

Answer:

See solution below

Step-by-step explanation:

According to the diagram shown

m<1 = m<5 = 5=65 degrees (corresponding angle)

m<5 = m<4 - 65 degrees (alternate interior angle)

m<9 = m<8 = 65degrees (corresponding angle)

m<5 = m<8 = 65dgrees (vertically opposite angles)

m<6+m<8 = 180

m<6 + 65 = 180

m<6 = 180 - 65

m<6 = 115degrees

m<2 = m<6 = 115degrees (corresponding angles)

m<6 = m<7 = 115degrees (vertically opposite angles)

m<3 = m<7 = 115degrees(corresponding angle)

)

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3 years ago
The abdominopelvic region that is bordered by all four imaginary lines is the
Ainat [17]

Umbilical point.

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In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

 

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

4 0
3 years ago
If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?
Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are c(x) = \frac{5}{x - 2} and d(x) = x + 3

So, (cd)(x) = (\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

8 0
3 years ago
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Find the solutions of the quadratic equation 2x2 + 6x - 2 = 0.
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Sorry didn't know how to write the answer so I just took a screen shot of my answer for you!

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3 years ago
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