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2 years ago

11

The berry-picking boxes at Bingo Berry Farm have square bottoms that are 8 centimeters on each side. Santiago fills his box with

raspberries to a height of 6 centimeters. What is the volume of raspberries in Santiago's box?

1 answer:

Pie2 years ago

6 0

You can solve this by doing 8×8×6 which gives you 384. Since we are finding the volume, you would do length times with times height. Hope this helps :-)

You might be interested in

Apply the rules for order of operstions to simplify 2 + 3 - 4 (5 × 4)

Lerok [7]

Just use PEMDAS
2+3-4 (5x4)

Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction So first is Parenthesis 5x4=20 next will be Addition because there are no exponents 2+3= 5-4= 1 so now we go back to multiplication 20 x 1= 20 so 20 is your answer.

Hope I helped out ^^

7 0

2 years ago

Mrs. Cooper has 51.2 pounds of soil. She uses 12.9 pounds of soil for her houseplants and 30.4 pounds of soil for her garden How

myrzilka [38]

Answer:

7.9

Step-by-step explanation:

She has a total of 51.2 and uses 12.9+30.4.

The equation would be 51.2-(12.9+30.4).

51.2-(12.9+30.4)

=51.2-43.3

=7.9

Have a nice day!!!!!!! :-)

<u>KA</u>

3 0

2 years ago

Enunciado:Si una empresa determina que sus costos obedecen a un modelo lineal y además sabe que si produce $10$ unidades sus cos

const2013 [10]

Responder:

y = 200x + 2000

Explicación paso a paso:

Deje que la ecuación lineal se exprese como y = mx + c

m es la pendiente

c es la intersección

Si la empresa produce $ 10 unidades, sus costos totales son $ 4000 dólares y si produce $ 15 unidades sus costos ascienden a $ 5000 dólares, entonces podemos representar esto como puntos de coordenadas;

(10,4000) y (15,5000)

Conseguir la pendiente

m = 5000-4000 / 15-10

m = 1000/5

m = 200

Obtener la intersección c

Sustituya m = 2000 y el punto (10, 4000) en la fórmula y = MX + c

4000 = 200 (10) + c

4000-2000 = c

c = 2000

Sustituya m = 200 y c = 2000 en la ecuación y = mx + c

y = 200x + 2000

Por tanto, la expresión lineal requerida es y = 200x + 2000

3 0

2 years ago

Pls answer the question attached

barxatty [35]

$\huge\mathfrak{\underline{answer:}}$

$\large\bf{\angle ACD = 105°}$

__________________________________________

$\large\bf{\underline{Here:}}$

BCD is an isosceles right triangle , right angled at D
ABC is an equilateral triangle

$\large\bf{\underline{To\:find:}}$

∠ ACD

$\large\bf{In\: triangle\:ABC:}$

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

$\large\bf{\underline{So}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = \frac{180}{3}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = 60°}$

$\large\bf{In\: triangle\:BDC}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle D = 90°}$

$\bf{⟼\angle DBC =\angle DCB }$ (Isosceles triangle)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DBC + \angle BDC + \angle DCB = 180° }$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB + 90° = 180°}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB = 180 -90}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = \frac{90}{2}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = 45°}$

$\large\bf{\underline{Therefore,}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = \angle ACB + \angle DCB}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = 60+45}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹\angle ACD = 105°}$

6 0

2 years ago

Sandra's scores on the first 4 tests were 87%, 92%, 76%,and 89%. What is the minimum score she needs to make on the fifth test s

sergejj [24]

Answer:

Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

Step-by-step explanation:

Given:

First 4 test scores = 87%, 92%, 76%,89%

Average targeted = 80%

We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.

Solution:

Let the minimum score she needs to make in fifth test be 'x'.

Total number of test = 5

Now we know that;

Average is equal to sum of all the scores in the test divided by number of test.

framing in equation form we get;

$\frac{87+92+76+89+x}{5}=80$

Multiplying both side by 5 we get;

$\frac{344+x}{5}\times 5=80\times 5\\\\344+x=400$

Subtracting both side by 344 we get;

$344+x-344=400-344\\\\x=56\%$

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.

5 0

2 years ago