From the information given, the rotated triangle is same as the original triangle. This is because, vertices of the rotation remain at the origin - (0,0).
<h3>What is the proof the above?</h3>
Notice that the question states: △A'B'C' is the image of △ABC. Given that the △ without primes is the original and the one with primes depict the rotated triangle,
under a rotation about the origin, (0,0) (0,0) (0, 0), indicating no movement,
△A'B'C' is in the same position with △ABC.
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Adding to the solutions and points gotten, we can further say that: Opposite angles of the parallelogram are congruent, by the theorem of Side Angle side (SAS) (i.e angle AEB = CED )
<h3>Meaning of Congruence</h3>
Congruence can be defined as a term used to depict a state of two object being equal, in harmony, and in agreement.
The congruence of a shaped is verified by some laws which they both must satisfy.
In conclusion, the triangle is congruent with the fact stated in the question and the additional fact added above.
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3z/2 = 9
z = 6.
6 x 3 = 18. 18/2=9
z. Again= 6
Answer:
perimeter of triangle IJH= 17.5
Step-by-step explanation:
line IJ is a midsegment, so you can divide the segments FH and GH by 2.
that means segment IH= 4.5 and segment GH=6. segment IJ is given as 7.
add 4.5 + 6 + 7, which equals 17.5
