Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
Answer:
Rewrite the first equation as x = 36 – 3y.
Step-by-step explanation:
x + 3y = 36 (1)
4x + 5y = 9 (2)
Using substitution method
From (1)
x = 36 - 3y
Substitute x = 36 - 3y into (2)
4x + 5y = 9
4(36 - 3y) + 5y = 9
144 - 12y + 5y = 9
- 12y + 5y = 9 - 144
-7y = -135
y = -135 / -7
y = 19.3
There is an error with the second equation, 4x + 5y can not be equal to 9
Nevertheless, the first step when solving by substitution is:
Rewrite the first equation as
x = 36 – 3y.
Answer:
See attachment
Step-by-step explanation:
To see clearly the graph that represents
we rewrite in vertex form to get;
This is a vertical parabola with vertex at (-1.5,-0.25) and opens upwards.
The required graph is shown in the attachment.
16.181818911918626382829229228282882828282.6272882