F(x)=3x²-6x+13
a=3, b=-6, c=13
the x coordinate of the vertex is x=-b/(2a), so x=-(-6)/(2*3)=1
when x=1, y=3(1)²-6(1)+13=10
the vertex is at (1,10)
answers are in bold.
Answer:
units
Step-by-step explanation:
If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.
We know the formula of length of perpendicular from a point 
to the straight line ax + by + c = 0 is given by
Therefore, in our case the perpendicular distance is
units. (Answer)
Answer:
x = 3/2
Step-by-step explanation:
2(x + 5) = 6x + 4
Open bracket first
2 × x + 2×5 = 6x + 4
2x + 10 = 6x + 4
Rewrite equation
6x + 4 = 2x + 10
Subtract 2x from both sides
6x - 2x + 4 = 2x - 2x + 10
4x + 4 = 10
Subtract 4 from both sides
4x + 4 - 4 = 10 - 4
4x = 6
Divide both sides by 4
4x/4 = 6/4
x = 6/4
Divide both denominator and numerator by 2
x = (6/4) ÷ 2
x = 3/2
I hope this was helpful, please rate as brainliest
Divide top and bottom by any number that's fits into both of them keep doing that until it's not possible Hope that helped Have a good day! :-)
Divide 7 into 9 and if you have a calculator it equals 0.77 repeating
