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3 years ago

10

The rectangle shown has a perimeter of 54 cm in a given area its length is seven more than four times its width write and solve

a system of equations to find the dimension of the rectangle please help

1 answer:

solniwko [45]3 years ago

6 0

Answer:

98 cm

because you cant add it

Step-by-step explanation:

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

Simplify<br><br>n-3 n-2/n^-6n^5<br><br>A) 1/n^-4<br>B)1/n^4<br>C)n^-6<br>D)n^4

pychu [463]

Answer:

Step-by-step explanation: was uuu

5 0

3 years ago

In ΔLMN, \overline{LN}

Karolina [17]

Answer:

$\bold{\angle NLM = 10^\circ}$

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

$\text{m}\angle MNO = (5x-13)^{\circ}$

$\text{m}\angle NLM = (x-4)^{\circ}$ and

$\text{m}\angle LMN = (2x+19)^{\circ}$

To find:

$\text{m}\angle NLM=?$

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

$\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14$

Putting the value of $x$ in $\angle NLM$ .

$\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}$

5 0

3 years ago

Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (9, –2) and (10, 2). Use (9, –2) as the po

True [87]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& -2~) 
% (c,d)
&&(~ 10 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{10-9}\implies \cfrac{2+2}{10-9}\implies \cfrac{4}{1}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=4(x-9)\implies y+2=4(x-9)$

4 0

3 years ago

The distance between 1 - 10 1/4

Pani-rosa [81]

The distance between 1 - 10 1/4

____________________

1 - 10 1/4 = -9 1/4

_________________________

Answer

-9 1/4

9 1/4 (in absolute value)

5 0

2 years ago

Read 2 more answers