Answer:
x = 13
y = -10
z = -7
Step-by-step explanation:
x+y+z=−4
2x+3y−2z=10
−x+2y−3z=−12
Add the first and the third equations to eliminate x
x+y+z=−4
−x+2y−3z=−12
--------------------
3y -2z = -16 Equation A
Add the second and twice the third equation to eliminate x
2x+3y−2z=10
−2x+4y−6z=−24
----------------------------
7y -8z = -14 Equation B
Take Equation A and multiply by -4
-4*( 3y -2z) = (-16)*-4
-12y + 8z = 64
Add this to Equation B
-12y + 8z = 64
7y -8z = -14
-----------------------
-5y = 50
Divide by -5
-5y/-5 = 50/-5
y = -10
Now using equation A
3y -2z = -16
3*-10 -2z = -16
-30 -2z = -16
Add 30 to each side
-2z = -16+30
-2z = 14
Divide by -2
-2z/-2 = 14/-2
z = -7
Now find x using the first equation
x+y+z = -4
x -7-10 = -4
x -17 = -4
Add 17 to each side
x-17+17 = -4+17
x = 13
Answer:
Goodnight
Step-by-step explanation:
<3 don't stay up late and get rest !
It’s a function because it passes the vertical line test
The circle goes thru the given points <span>(3,-4) And (3,5). Since the x-coordinate does not change, the diameter lies right on the vertical line x=3. Since the vertical distance between these points is 5-(-4), or 9, the radius is 9/2.
The standard eq'n of a circle is (x-h)^2 + (y-k)^2 = r^2
Let's subst. what we know: we get (x-3)^2 + (y-1/2)^2 = (9/2)^2. Note that y = 1/2 is halfway between y=-4 and y=5.</span>
Answer:
Monday:
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><em>3</em>
<em>Tablespoon</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><u><em>3</em><em>0</em></u>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><u><em>7</em><em>5</em></u>
Wednesday
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><u><em>1</em><em>.</em><em>1</em><em>2</em></u>
<em>Tablespoons</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><em>2</em><em>8</em>