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Morgarella [4.7K]

3 years ago

10

Craig Browning bakes cookies for the elementary school cookie sale. His chocolate chip cookies sell for $1.00 a dozen, and his o

atmeal brownie cookies sell for $1.50 a dozen. He will bake up to 20 dozen chocolate chip cookies, and up to 40 dozen oatmeal brownie cookies, but no more than 50 dozen cookies, total. Also, the number of oatmeal brownie cookies will be no more than three times the number of chocolate chip cookies. How many of each kind should Craig make in order for the elementary school to make the most money

1 answer:

Volgvan3 years ago

8 0

Answer and Step-by-step explanation:

Let

Number of chocolate chip cookies = x

Number of oatmeal brownie cookies = y

Bake chocolate chip cookies up to 20 dozen = x≤ 20

Bake oatmeal brownies up to 40 dozen= y≤40

Total cookies = x + y ≤ 50

Number of oatmeal brownie will be no more than three times the number of chocolate chip= y≤3x

From the inequality:

X + y=50

y = 3x

By putting the value of y, we get

x + 3x = 50

4x = 50

X = 12.5

By putting the value of x=12.5 in equation y = 3x, we get

Y = 3(12.5)

= 37.5

Craig should make 12.5 dozen chocolate chip and 37.5 dozen oatmeal brownies in order to make more money.

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2 years ago

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3 years ago

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For a left-tail test at a 5% significance level, we have a critical value of z that is zc=-1.645. This value is the limit of the rejection region. That means that if the test statistic z is smaller than zc=-1.645, the null hypothesis is rejected.

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$p_c=\pi+z_c\cdot\sigma_p=0.58-1.645*0.04=0.58-0.0658=0.5142$

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$P(p$

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The only variable left to change in the test in order to increase the power of the test is the sample size, as the significance level can not be changed (it is related to the probability of a Type I error).

It the sample size is increased, the standard error of the proprotion decreases. As the standard error tends to zero, the critical proportion tend to 0.58, as we can see in its equation:

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