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Artemon [7]
3 years ago
11

15. Over what range of angles does the value of sin(O) consistently increase?

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

D. 0° to 90°

Step-by-step explanation:

If we see curve of sin(o) on coordinate,  we will notice that value of sin curve increases from 0 to 90 degrees and then decreases from 90 to 180 degrees.

Hence option D is correct.

Alternatively

we see that

sin 0 = 0

sin 30 = 1/2

sin 45 = 1/\sqrt{2}

sin 60 = \sqrt{3} /2

sin 90 = 1

Thus, we see  that value of sin is increasing from 0 to 90

now lets see value of sin from 90 to 180

sin 90 = 1

sin 120 = \sqrt{3} /2

sin 135 = 1/\sqrt{2}

sin 150 = 1/2

sin 180 = 0

Thus, we see  that value of sin is decreasing from 90 to 180.

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Come up with a rule for adding integers.
Digiron [165]

Answer:

The sum of any integer and its opposite is equal to zero. Summary: Adding two positive integers always yields a positive sum; adding two negative integers always yields a negative sum. To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
2 years ago
23 points to whoever can answer this question !!
yKpoI14uk [10]

I do believe that that point is -2.2 because of the fact that the difference between -1.6 and -2.4 is 0.8, and there are 4 marks in between them. So each mark's value is decreased by -0.2.

5 0
3 years ago
Read 2 more answers
Help Study Island Is out to get me!!!
Digiron [165]

Answer:

The <u>correct answer</u> would most likly be C. Triangle JKL is similar to triangle RST.

Step-by-step explanation:

In the question, we see that triangles JKL and RST have the same slope at lines JL and RT. <u>Triangles with equal slopes are not necessarily congruent; however, it means that they are similar.</u> Therefore , Triangles JKL and RST are similar

Thanks Have a good day!

8 0
2 years ago
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Can you graph 6=6? infinite solutions
ad-work [718]

Answer:

it is infinitive solutions because if you do the work you'll find that its infinite solutions...bye rate 1 thx rate more if you think i was wrong just kidding ik im right just say if its helpful ...thx

Step-by-step explanation:

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2 years ago
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