Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Hello! I'll write the instructions to graph these functions.
f(x)=x
Technically, this function is y=x, so the slope would be 1. To graph this one, start at the origin (0,0) and move up one unit, and to the right one unit since this is a positive slope.
g(x)= -1/3x+2
First, plot a point at y=2 when x=0. 2 is your y-intercept. Your slope is negative, so the line will be decreasing. From your first point, head down 1 unit and to the right 3 units. Continue plotting points from the previous points.
Also, if you have a graphing calculator, here are the steps to graphing the functions: ON, Y= (enter your functions), and press GRAPH or 2nd, TABLE to see individual points. Hope this helps! :)
Answer:
-48
Step-by-step explanation:
This is your perfect answer
Area of a trapezoid is A=height over 2 B1 +B2, so 10+10=20, then 20(8)=160, 160/2=80. Answer is b.