<span>
If BA is d units the CB must be 2d units. B is on the x-axis, 2d units
right of C so its coordinates are (2d, 0). A is d units above B at (2d,
d). </span>
Answer: x=5
Step-by-step explanation:
Substitute 17 for n(x)
17=2x+7
Subtract 7 from both sides
10=2x
Divide each side by 2 to get the x by itself
x=5
Answer:

Step-by-step explanation:
The functions are;

and

We want to find

First we find g(-4) to get:



Now

This implies that,



Answer:
<em>x = 17°, m∠ A = 114°</em>
Step-by-step explanation:
We can tell that these pair of angles are corresponding, provided;
Line 1 ║ Line 2, AB ∩ Line 1 and Line 2 ⇒ corresponding ∠s ≅,
m∠ A = m∠ B ⇒ Substitute values of A and B,
6x + 12 = 3x + 63 ⇒ Subtract 3x on either side,
3x + 12 = 63 ⇒ Subtract 12 on either side of equation,
3x = 51 ⇒ Divide either side by 3,
<em>x = 17 </em>⇒ Substitute value of x to solve for m∠ A,
m∠ A = 6 * ( 17 ) + 12,
m∠ A = 102 + 12,
<em>m∠ A = 114</em>
<em>Solution; x = 17°, m∠ A = 114°</em>
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