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Elodia [21]
3 years ago
6

Kara earns 12 cent for each paper she delivers. If she delivers papers to 42 customers each day, how much does she earn in 1 wee

k ?
Mathematics
2 answers:
Andrew [12]3 years ago
6 0

12x42=504

504 cents earned every day when 42 papers are delivered

For a week= 504x7

3528cents

Bogdan [553]3 years ago
6 0

Answer:

3,528 cents = 35 dollars and 28 cents

Step-by-step explanation:

She earns 12 cents for each paper delivered.

=> She earns: 12 x 42 = 504 cents a day

=> She earns: 12 x 42 x 7 = 3528 cents in 1 week.

That is probably the answer you're expecting.

But you shouldn't.

One customer might need more than 1 paper a day, so there's no clear answer to your question.

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The mean resting pulse rate for men is 72 beats per minute. A simple random sample of men who regularly work out at Mitch's Gym
BARSIC [14]

Answer:

We conclude that the mean resting pulse rate for men is 72 beats per minute.

Step-by-step explanation:

We are given that he mean resting pulse rate for men is 72 beats per minute. Assume that the standard deviation of the resting pulse rates of all men who work out at Mitch's Gym is known to be 2.6 beats per minute.

A simple random sample of men who regularly work out at Mitch's Gym is obtained and their resting pulse rates (in beats per minute) are listed below;

87, 89, 69, 63, 70, 65, 88, 84, 58, 53, 66, 70.

Let \mu = <u><em>mean resting pulse rate for men.</em></u>

SO, Null Hypothesis, H_0 : \mu = 72 beats/minute     {means that the mean resting pulse rate for men is 72 beats per minute}

Alternate Hypothesis, H_A : \mu < 72 beats/minute      {means that the mean resting pulse rate for men is less than 72 beats per minute}

The test statistics that would be used here <u>One-sample z-test statistics</u> as we know about population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mean resting pulse rate = \frac{\sum X}{n}

                =  \frac{87+ 89+ 69 +63 +70 +65+ 88+ 84+ 58+ 53+ 66+ 70}{12}  = 71.83 beats/minute

            \sigma = population standard deviation = 2.6 beats per minute

            n = sample of men = 12

So, <u><em>the test statistics</em></u>  =  \frac{71.83 - 72}{\frac{2.6}{\sqrt{12} } }    

                                     =  -0.23

The value of z test statistics is -0.23.

<u></u>

<u>Also, P-value of the test statistics is given by;</u>

            P(Z < -0.23) = 1 - P(Z \leq 0.23)

                                 = 1 - 0.59095 = <u>0.40905</u>

Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.23 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the mean resting pulse rate for men is 72 beats per minute.

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D.

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3(x-1)-8=4(1+x)+5  

One solution was found :

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((3•(x-1))-8)-(4•(x+1)+5)  = 0  

Step  2  :

Equation at the end of step  2  :

 (3 • (x - 1) -  8) -  (4x + 9)  = 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  -x - 20  =   -1 • (x + 20)  

Equation at the end of step  4  :

 -x - 20  = 0  

Step  5  :

Solving a Single Variable Equation :

5.1      Solve  :    -x-20 = 0  

Add  20  to both sides of the equation :  

                     -x = 20

Multiply both sides of the equation by (-1) :  x = -20

One solution was found :

                  x = -20

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The box has 450 bars in it. 18 times 25 would equal 450
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