Answer:
55- 3m is the awnser for this question
Answer:
i. Slope=-1/6
ii. Midpoint= (1,8.5)
iii. <em>Distance</em><em>=</em><em> </em><em>√</em><em>3</em><em>7</em><em> </em><em>units</em>
<em>iv.</em><em> </em><em> </em><em> </em><em> </em><em>Slope </em><em>of </em><em>t=</em><em>2</em>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
The anwer of this question is c
Answer:
9 times
Step-by-step explanation:
Area = length x breadth
area of picture not enlarged = 3 x 5 = 15in²
If length is tripled it becomes , 3 x 3 = 9in
If width is tripled, it becomes , 5 x 3 = 15in
Area of enlarged picture = 9in x 15in = 135in²
amount by which enlarged image is larger = 135in² /15in² = 9
Answer:
3rd graph or C would be correct
Step-by-step explanation:
Took test on edge