Answer:
public class Main
{
public static void main(String[] args) {
String[] strs = new String[10];
java.util.Scanner sc = new java.util.Scanner(System.in);
for(int i = 0; i < 10; i++){
System.out.print("Enter string " + (i+1) + ":");
strs[i] = sc.nextLine();
}
System.out.println("The strigs with even number of characters is");
for(int i = 0; i < strs.length;i++){
if(strs[i].length() % 2 == 0){
System.out.println(strs[i]);
}
}
}
}
Explanation:
In order to get the frequency of this light you have to d<span>ivide the speed of light by the wavelength.
The formula: </span>
<span>
Set the values in the appropriate form:</span>
Solution:
The answer: = 63.8PHz
Answer:
VM escape attack
Explanation:
<em>In a VM escape attack, the attacker exploits hypervisor vulnerabilities to gain control over resources reserved for other guest operating systems. Services operating on the guest may be exposed to the other attacks, but such attacks can only access data allotted to the same guest. In the event of a buffer overflow or directory traversal or the client in the case of cross-site scripting.</em>
Answer:
A
Explanation:
TCP numbers the packets before sending them so that the receiver can correctly reorder the packets, and it can request missing packets be resent.
UDP- sends all the packets at once
IP- rules on the networks
HTTP- used for transmitting web pages over the Internet
