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Naya [18.7K]
3 years ago
11

12.) Write y = 1/6 x + 7 in standard form using integers.

Mathematics
1 answer:
Trava [24]3 years ago
3 0

Option A

-x + 6y = 42 is the standard form

<u>Solution:</u>

Given that we have to write y = \frac{1}{6}x+7 in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

y = \frac{1}{6}x+7

Let us convert the above equation into standard form

y = \frac{x}{6} + 7

y = \frac{x}{6} + \frac{7}{1}

Make the denominator same in R.H.S

y = \frac{x}{6} + \frac{7 \times 6}{1 \times 7}

Solve the above equation

y = \frac{x}{6} + \frac{42}{6}

y = \frac{x+42}{6}

Move 6 from R.H.S to L.H.S

6y = x + 42

Bring all the terms to one side, leaving only constant on R.H.S

-x + 6y = 42

The above equation is of form Ax + By = C

Thus option A is correct

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Find the midpoint of a and b where a has coordinates (2,3) and b has coordinates (8,9).
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A standard roll of toilet paper is 304 feet long. If Bob walks at a steady rate of five feet per second, how much time does it t
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Answer:

1.01 minutes

Step-by-step explanation:

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3 years ago
1/4x+3/4y=1 please solve (linear equation)
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subtract 1/4x, 

3/4y=1-1/4x

then multiply my 4/3

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6 0
3 years ago
(10+-7 - -2) / (-2 - -1)
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Nice use of brackets. We know exactly what you mean.

(10 - 7 + 2) / (-2 + 1) Notice that with an even number of - signs, you get a plus and with and odd number you get a minus.

(5) / (-1) = - 5 answer

Edit

Numerator

10 does not change.

+ - 7 Here a plus and a minus are put together. There is 1 minus sign which is an odd number of minus signs so the 7 is minus

- - 2 Here there are 2 minus signs. They become plus because 2 is even, and an even number of minuses become a plus so you have +2

10 - 7 + 2 = 5

Denominator

-2 does not change. It remains minus 2.

- - 1 There are 2 minus signs so this becomes plus 1.

- 2 + 1 = - 1

Numerator over denominator = 5/-1 = - 5. I'll probably run out of editing time. If you still don't understand, try and pinpoint the problem and we'll keep trying until you do see it. This question is worth it.

4 0
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