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marin [14]
3 years ago
5

What is the ratio that compares 6 games to the total 41 games played?

Mathematics
1 answer:
atroni [7]3 years ago
4 0
The ratio that compares 6 games to the total 41 games played is 6:35. if it was probability, it would be 6/41.
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2 rational numbers who’s difference is rational
horrorfan [7]

Answer: (5+√2) and (3+√2)

Step-by-step explanation: Let (5+√2) and (3+√2) be  two irrational numbers

                                             Difference = (5+√2) - (3+√2)

                                             Difference = 2

                                             2 is a rational number

6 0
3 years ago
a developer wants to develop 5 acres of land. Each lot in the develope is to be 1/12 of an acre. How many lots will the land dev
Nitella [24]
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3 years ago
Write the standard equation of the circle with the given center that passes through the given point
Kitty [74]
Circle equation
(x - h)^2 + (y - k)^2 = r^2
Since radius isn't given use the center and point, with the distance formula, to find the radius.
D=sqrt((x2-x2)^2+)y2-y1)^2)
D=sqrt((1-0)^2+(2-6)^2
D=sqrt(1+16)
D=sqrt 17
radius = sqrt 17
(h, k) is the center and r is the radius
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5 0
3 years ago
Help me pleasee I really<br> Need help
DanielleElmas [232]
We can’t measure these. How long is each of them
6 0
3 years ago
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
beks73 [17]
So, how much acid is there in 6 gallons?  well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it?  well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it?  (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\&#10;&------&------&------\\&#10;\textit{pure acid}&x&1.00&x\\&#10;\textit{20\% sol'n}&6&0.20&1.2\\&#10;------&------&------&------\\\&#10;mixture&y&0.90&0.9y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+6=\boxed{y}\\&#10;x+1.2=0.9y\\&#10;----------\\&#10;x+1.2=0.9\left( \boxed{x+6} \right)&#10;\end{cases}&#10;\\\\\\&#10;x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2&#10;\\\\\\&#10;x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}
3 0
3 years ago
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