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Dafna1 [17]
3 years ago
13

how many fewer rainy days are there than sunny and cloudy days when there are 6 sunny days, 4 cloudy days and 7 rainy days

Mathematics
1 answer:
Cloud [144]3 years ago
8 0
3 more fewer days because 6+4=10 and 10-7=3.

Hope that helped:)
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10p+9-11-p=-2(2p+4)-3(2p-2)
Sergeu [11.5K]
9p-2=-4p-8-6p+6
9p-2=-10p-2
+10
19p-2=-2
+2 +2
19p
4 0
3 years ago
Solve the following inequality: x+5≤(−x+2)+x
vesna_86 [32]

Answer:

<h2>x ≤ - 3</h2>

Step-by-step explanation:

x + 5 ≤ ( - x + 2) + x

<u>Remove the parenthesis</u>

That's

x + 5 ≤ - x + 2 + x

x + 5 ≤ 2

Using the subtraction property subtract 5 from both sides

That's

x + 5 - 5 ≤ 2 - 5

x ≤ 2 - 5

We have the final answer as

<h3>x ≤ - 3</h3>

Hope this helps you

4 0
3 years ago
The movie Avatar is the number one movie in U.S. history, earning $760,507,625. The second place movie is Titanic, earning $600,
Harman [31]
The answer is 78.99%, So rounded up to 79%

plz thank me, it keeps me motivated to answer more of your questions :)

4 0
3 years ago
Read 2 more answers
Consider Functions F and G
Zanzabum

Answer:

A

Step-by-step explanation:

We are given two functions:

\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}

And we want to find:

f(x)+g(x)

Thus:

\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}

We can factor the denominator of the first term:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)

Multiply:

\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}

Combine:

\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}

Simplify:

\displaystyle =\frac{2x-20}{(x+10)(x-4)}

We can expand the denominator:

\displaystyle =\frac{2x-20}{x^2+6x-40}

Therefore, our answer is A.

6 0
3 years ago
Read 2 more answers
Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4
docker41 [41]

Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

y + 4 = C \cdot (x-k)^{2}

The formula is now expanded into a the form of a second-order polynomial:

y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}

y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)

The general equation of the second-order polynomial is:

x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}

x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}

x = k \pm 2\cdot \frac{\sqrt{C}}{C}

x = k \pm \frac{2}{\sqrt{C}}

The equations to be solved are presented herein:

-3 = k -\frac{2}{\sqrt{C}}

5 = k + \frac{2}{\sqrt{C}}

Now, the solution of the system is:

-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}

\frac{4}{\sqrt{C}} = 8

\sqrt{C} = \frac{1}{2}

C = \frac{1}{4}

k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}

k = 1

The equation of the parabola is:

y = \frac{1}{4}\cdot (x-1)^{2} -4

Lastly, the graphic of the function is included as attachment.

3 0
3 years ago
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