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Dafna1 [17]
4 years ago
13

how many fewer rainy days are there than sunny and cloudy days when there are 6 sunny days, 4 cloudy days and 7 rainy days

Mathematics
1 answer:
Cloud [144]4 years ago
8 0
3 more fewer days because 6+4=10 and 10-7=3.

Hope that helped:)
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Which of the following is a true statement?
Rudik [331]

Answer:

A. All real numbers are rational numbers

Good luck!

5 0
4 years ago
What is x?? I'm so confused!
LiRa [457]

Answer:

x = 468%

Step-by-step explanation:

I see a proportion here.

we want to solve for the variable x in the proportion:

18% / (2 weeks) =   ( x %) / (52 weeks)

here we should multiply 52 to boths sides

(52 weeks) * 18%  / (2 weeks) =   x %

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3 0
3 years ago
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
Evaluate the expression. If necessary, round to the nearest hundredth.<br><br> log 2.8
Marrrta [24]
<span>the answer is 0.447158 and rounded it is 0.45
</span>
8 0
4 years ago
Read 2 more answers
Solve the following equation for I. A = 2 πr + πrl. Explain each step.<br> BRAINLY IF CORRECT
hram777 [196]

Answer:

Step-by-step explanation:

A  = 2π +πrl                

A - 2π = πrI                  subtract by 2π

(A- 2π)/(πr) = I               divide by πr to isolate I

4 0
3 years ago
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