Right answer gets brainlist

What are the missing parts that correctly complete the proof?

kap26 [50]

Point b and point a need to be drawn vertically

5 0

3 years ago

Which equation is the slope-intercept form of the line that passes through (12, 9) and is perpendicular to the graph of y = −34x

noname [10]

Answer:did

Step-by-step explanation:I do that.

8 0

3 years ago

Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw

vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so $a = 40, b = 65$

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

$P(X < 50) + P(X \geq 50) = 1$

The intervals can be open or closed, so

$P(X < 50) = P(X \leq 50)$

We have that

$P(X \geq 50) = 1 - P(X < 50)$

$P(X < x) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6$

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is $P(X \leq 55)$

$P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6$

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

$M = \frac{a+b}{2}$

So

$M = \frac{40+65}{2} = 52.5$

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

So

$S = \sqrt{\frac{(65-40)^{2}}{12}}$

$S = 7.22$

The standard deviation is 7.22 minutes.

5 0

3 years ago

Chicago is home to 2.706 million people and the city sees approximately 55 million visitors each year. China has a population of

Norma-Jean [14]

China could expect a quantity of visitors of 8.512 × 10⁶ in Chicago.

<h3>How to apply direct proportions</h3>

A <em>direct</em> proportion is a <em>direct</em> relationship between two variables, which in this case is represented between the quantity of tourists in the city of Chicago and the population of the country of origin.

Let suppose the existence of direct proportionality and world has a population of 9000 million people, the quantity of Chinese visitors in the city of Chicago is determined by the following formula:

x = (1.393 × 10⁹ / 9 × 10⁹) × 55 × 10⁶

x = 8.512 × 10⁶

China could expect a quantity of visitors of 8.512 × 10⁶ in Chicago. $\blacksquare$

To learn more on direct proportions, we kindly invite to check this verified question: brainly.com/question/14389660

3 0

3 years ago

A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walker charge for a 45 minute

diamong [38]

Answer:

- False

- True

- false

Step-by-step explanation:

- The variable that changes is the price

- 30 is the slope and 6 is the y-int

- 30(.75) + 6 = 28.5

5 0

3 years ago