Let, larger number be x and smaller number be y.
Condition 1: The summ of two numbers is 134.
It can be written as,
Condition 2: If three times the smaller number is subtracted from the larger number, the result is 18.
The equation is,
Solving equation 1 and 2,
Out the value of y=29 in equation (1),
Answer:
Larger number is x=105
Smaller number is y=29.
1/5=20%
4 gallons. 100%
x gallons. 20%
x=4•20/100
x=80/100
x=8/10
x=4/5
Mrs. Zirkle will use 4/5 gallons of milk.
I am not 100% sure.
Answer:
241 clients
Step-by-step explanation:
His problem can be solved using the principle of proportionality or rule three.
We can take advantage of the proportion between respondents who tell us the number of respondents and how many expect to go on vacation and the total number of workers, therefore:
Respondents /// Whole company
Vacations 21 x
Total 45 516
then x equals:
x = (516 * 21) / (45)
x = 240.8
x = 241 clients
This means that approximately 241 clients expect to go on vacation throughout the company.
Answer:
60 + 12 * g, with g representing the number of extra gigabytes
Step-by-step explanation:
First, we know that Maritza has to pay $60 for 10GB of data, no matter what. Therefore, the base cost of the cell phone plan is 60 dollars, and all extra costs must be added to that. Currently, our expression is therefore 60 + something = cost of cell phone plan.
After that, the plan costs $12 for each gigabyte of data past 10 GB. This means that, for example, if Maritza uses 11 gigabytes, the plan will cost 60 (the base amount) + 12 for each gigabyte past 10 GB. There are 11-10=1 extra gigabytes, so the cost is 60 + 12 * 1 = 72 dollars. For each extra gigabyte, 12 dollars are added, so we can represent this as
60 + 12 * g, with g representing the number of extra gigabytes
Sum of the numbers in the set: 42+37+32+29+20 =160
Current mean: 160/5 = 32
Median = the valvue of the middle = 32.
New mean: 32+10= 42.
Sum of numbers in the new set = 42*8 = 336
Difference: 336 - 160 = 176
I want to include 32, so that the new median stays in 32.
So the other two numbers must add 176 - 32 = 144
I will use a smaller number than 32 and the other greater (again in order to keep the same median.
I will choose 28 and 144 - 28 = 116.
So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}
Checking:
Sum of the terms: 116+42+37+32+32+29+28+20 = 336
Mean = 336 / 8 = 42, which is 10 more than the original mean.
And the new median is (32+32)/2 = 32. The same of the original set.
