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Anon25 [30]
3 years ago
5

Olivia spent $20.00 on pencils and pens. Each pencil cost $2.00, and each pen cost $2.50. Which equation represents the number o

f pencils, x, and the number of pens, y, Olivia could have bought?
Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0

Answer: $2.00x + $2.50y = $20.00

Step-by-step explanation:

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Under her cell phone plan, Rajani pays a flat cost of $65 per month and $5
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Peggy earned $20 for each lawn she mowed last summer. This summer, she raised her price to $23 per lawn. What is the percent inc
anyanavicka [17]

Answer:

15 percent

Step-by-step explanation: You will substract the new value from the old value.

23-20

Now you will get the difference between them and divide that by the original amount.

3/20

This will equal 0.15 in which you now multiply by 100

15 percent

5 0
2 years ago
Kyle mixes 45 grams of popcorn with 15 grams of powdered cheese. How much popcorn does Kylebuse per gram of cheese?
nekit [7.7K]

Answer:

B

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7 0
3 years ago
In the expression, x^2 + 6x + 9, which is the coeffcient?
ikadub [295]

The coefficient is the number next to the letter.

Although the x squared term has a coefficient of 1, it is not listed in the answer choices. However, the coefficient of the middle term 6x is listed.

Answer: 6

3 0
3 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
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