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3 years ago

Each of the 6 cats in a pet store was weighed. Here are their weights (in pounds):

1 answer:

7 0

Mean: add up all numbers and divide by the number of data
12 + 12 + 7 + 5 + 10 + 16 = 62
62/6 = 10.333... (mean)
5,7,10,12,12,16
Find what’s in the middle
The medium is 11

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72 divided by negative 9

Nataly [62]

72 divided by negative 9 is -8

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2 years ago

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In the scale drawing, what will the length of the west side of the backyard?

Shtirlitz [24]

The diagram shows a lawn with the north side measuring 50 units and the west side measuring 28 units. The deck is scaled down by a factor of 1/5.

This is because the ratio of the length of the lawn to that of the deck is 1 : 5.

Hence we can now ca

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1 year ago

3.) Write an inequality for the phrase "two more than three times a number is at

stiks02 [169]

Answer:

3x + 2 ≤ 53

Step-by-step explanation:

"2 more than" means that there will be a + 2 in the equation. "3 times a number" means that 3 is multiplied by an unknown number which can be represented by a variable such as x. "At most" means less than or equal to, since the number cannot be greater than.

So generally, you might want to write the equation as 2 + 3x ≤ 53, but 2 + 3x is not in y = mx + b form. Basically, you need to write it as 3x + 2 ≤ 53 because that's how math works.

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3 years ago

-6+2=<br> I also need help on how to show work

asambeis [7]

Answer:

-4

Step-by-step explanation: if the signs are different subtract the values and take the sign of the larger number!

- - - - - -

+ +

8 0

3 years ago

A data set includes data from student evaluations of courses. The summary statistics are nequals83, x overbarequals3.32, sequa

Andrews [41]

Answer:

Hypothesis

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

$\bar X=3.32$ represent the sample mean

$s=0.56$ represent the sample deviation

$n=83$ sample size

$\mu_o =3.5$ represent the value to test

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0

2 years ago