Answer:
3rd one 1000 times greater
Step-by-step explanation:
first you make 10^9 into 1000000000 then you make 10^6 into 1000000 then you divide them both and you get 1000
Answer:
-11, -51 and -251
Step-by-step explanation:
The inicial value of x is -3
Now, to know the other three iterates of the function, we just need to calculate the value of the function, and them use this value as the input value for the function three times:
the first iterate is found using x0 as x:
f(-3) = 5*(-3) + 4 = -11
Now, we use x = -11 in the function to find the second iterate:
f(-11) = 5*(-11) + 4 = -51
Nowwe use x = -51 in the function to find the third iterate:
f(-51) = 5*(-51) + 4 = -251
So, the first three iterates of the function, given initial value x0 = -3, are -11, -51 and -251.
well, we know that 1ft³ = 7.48 gallons, alright, we have a volume in gallons and a diameter in feet, so if we were to use the diameter in feet to get the volume what we would end up will be a volume in ft³, so let's convert firstly the gallons to ft³ then
![750g\cdot \cfrac{ft^3}{7.48g}\implies 750g\cdot \cfrac{ft^3}{~~\frac{748}{100}g~~}\implies \cfrac{18750}{187}ft^3](https://tex.z-dn.net/?f=750g%5Ccdot%20%5Ccfrac%7Bft%5E3%7D%7B7.48g%7D%5Cimplies%20750g%5Ccdot%20%5Ccfrac%7Bft%5E3%7D%7B~~%5Cfrac%7B748%7D%7B100%7Dg~~%7D%5Cimplies%20%5Ccfrac%7B18750%7D%7B187%7Dft%5E3)
why do I use a fraction? for the sake of not losing value in the rounding, so let's use the fraction for the volume of a right-circular cylinder
![\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} h=height\\ r=radius\\[-0.5em] \hrulefill\\ r = \stackrel{\textit{half diameter}}{2}\\ V=\frac{18750}{187} \end{cases}\implies \cfrac{18750}{187}=\pi (2)^2h \\\\\\ \cfrac{18750}{187(4\pi )}=h\implies \stackrel{ft}{7.979}~\approx~h\implies \stackrel{\textit{converting to inches}}{7.979\cdot 12\approx h}\implies \stackrel{\textit{rounded up}}{\stackrel{in}{96}\approx h}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%20V%3D%5Cpi%20r%5E2%20h~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%20%3D%20%5Cstackrel%7B%5Ctextit%7Bhalf%20diameter%7D%7D%7B2%7D%5C%5C%20V%3D%5Cfrac%7B18750%7D%7B187%7D%20%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7B18750%7D%7B187%7D%3D%5Cpi%20%282%29%5E2h%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B18750%7D%7B187%284%5Cpi%20%29%7D%3Dh%5Cimplies%20%5Cstackrel%7Bft%7D%7B7.979%7D~%5Capprox~h%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bconverting%20to%20inches%7D%7D%7B7.979%5Ccdot%2012%5Capprox%20h%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B%5Cstackrel%7Bin%7D%7B96%7D%5Capprox%20h%7D)
Explanation:
The test grade for 1st three tests = 62, 85, 89
Let the fourth test score = x
The result we hoping to get is grade B.
Let's find the average of the four test score
![\text{Average = }\frac{Su\text{ m of all test score}}{nu\text{mber of test score}}](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20%3D%20%7D%5Cfrac%7BSu%5Ctext%7B%20m%20of%20all%20test%20score%7D%7D%7Bnu%5Ctext%7Bmber%20of%20test%20score%7D%7D)
![\begin{gathered} s\text{ um of test scores = 62 + 85 + 89 + x} \\ nu\text{mber of test score = 4} \\ \frac{\text{62 + 85 + 89 + x}}{4}=\text{ Average} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20s%5Ctext%7B%20um%20of%20test%20scores%20%3D%2062%20%2B%2085%20%2B%2089%20%2B%20x%7D%20%5C%5C%20nu%5Ctext%7Bmber%20of%20test%20score%20%3D%204%7D%20%5C%5C%20%5Cfrac%7B%5Ctext%7B62%20%2B%2085%20%2B%2089%20%2B%20x%7D%7D%7B4%7D%3D%5Ctext%7B%20Average%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} A\text{ grade B represents atleast 80} \\ \text{Atleast represents }\ge \\ \frac{\text{62 + 85 + 89 + x}}{4}\text{ }\ge\text{ 80} \\ \frac{\text{236 + x}}{4}\text{ }\ge\text{ 80} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%5Ctext%7B%20grade%20B%20represents%20atleast%2080%7D%20%5C%5C%20%5Ctext%7BAtleast%20represents%20%7D%5Cge%20%5C%5C%20%5Cfrac%7B%5Ctext%7B62%20%2B%2085%20%2B%2089%20%2B%20x%7D%7D%7B4%7D%5Ctext%7B%20%7D%5Cge%5Ctext%7B%2080%7D%20%5C%5C%20%5Cfrac%7B%5Ctext%7B236%20%2B%20x%7D%7D%7B4%7D%5Ctext%7B%20%7D%5Cge%5Ctext%7B%20%2080%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \text{236 + x }\ge\text{ }80(4) \\ \text{236 + x }\ge\text{ }320 \\ \text{subtract }236\text{ from both sides:} \\ 236\text{ - 236 + x }\ge\text{ }320\text{ - 23}6 \\ x\text{ }\ge\text{ 84} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B236%20%2B%20x%20%7D%5Cge%5Ctext%7B%20%7D80%284%29%20%5C%5C%20%5Ctext%7B236%20%2B%20x%20%7D%5Cge%5Ctext%7B%20%7D320%20%5C%5C%20%5Ctext%7Bsubtract%20%7D236%5Ctext%7B%20from%20both%20sides%3A%7D%20%5C%5C%20236%5Ctext%7B%20-%20236%20%2B%20x%20%7D%5Cge%5Ctext%7B%20%7D320%5Ctext%7B%20-%2023%7D6%20%5C%5C%20x%5Ctext%7B%20%7D%5Cge%5Ctext%7B%20%2084%7D%20%5Cend%7Bgathered%7D)
This means Cassie needs to score 84 or more to get a grade of B
In ineq