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snow_lady [41]
2 years ago
13

Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)

Mathematics
1 answer:
inessss [21]2 years ago
6 0

Answer:

The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

Step-by-step explanation:

Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)

The function rule is of form: \mathbf{y=mx+b}

where m is slope and b is y-intercept

Finding slope:

The formula used to find slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=0, y_1=0, x_2=5, y_2=-13

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-13-0}{5-0}\\Slope=\frac{-13}{5}\\Slope=-\frac{13}{5}

Finding y-intercept

We will use point(0,0) to find y-intercept

y=mx+b\\0=-\frac{13}{5}(0)+b\\0=0+b\\b=0

So, y-intercept is 0

The Function rule for line having slope m=-13/5 and y-intercept b=0:

y=mx+b\\y=-\frac{13}{5}x+0\\y=-\frac{13}{5}x

So, The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

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Answer:

A≈113.1cm²

Step-by-step explanation:

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I need help with my algebra 2. I also want to know how to solve this.
Lisa [10]

Add 1 to both sides:

\sqrt{x+3} = x+1

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

x+1 \geq 0 \iff x \geq -1

Under this assumption, we square both sides and we have

x+3 = (x+1)^2 \iff x+3 = x^2+2x+1 \iff x^2+x-2 = 0

The solutions to this equation are

x = -2,\ x=1

But since we can only accept solutions greater than -1, we discard x=-2 and accept x=1.

In fact, we have

x=-2 \implies \sqrt{-2+3}-1=0\neq -2

and

x=1 \implies \sqrt{4}-1=1

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4 0
3 years ago
Describe a real-world situation that the graph could represent. Then describe the possible values for each variable
Alex777 [14]

Answer:

Speed=distance/time i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

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So, if we take distance on y axis and time on x axis with points as (distance,time)

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(2,2) ==> v=2/2=1

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

8 0
3 years ago
4) What is the total cost (tax and price) on a purchase of $108.50 if the sales tax is 8%?
vitfil [10]
Answer: C)$117.18

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4 0
2 years ago
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