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snow_lady [41]
3 years ago
13

Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)

Mathematics
1 answer:
inessss [21]3 years ago
6 0

Answer:

The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

Step-by-step explanation:

Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)

The function rule is of form: \mathbf{y=mx+b}

where m is slope and b is y-intercept

Finding slope:

The formula used to find slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=0, y_1=0, x_2=5, y_2=-13

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-13-0}{5-0}\\Slope=\frac{-13}{5}\\Slope=-\frac{13}{5}

Finding y-intercept

We will use point(0,0) to find y-intercept

y=mx+b\\0=-\frac{13}{5}(0)+b\\0=0+b\\b=0

So, y-intercept is 0

The Function rule for line having slope m=-13/5 and y-intercept b=0:

y=mx+b\\y=-\frac{13}{5}x+0\\y=-\frac{13}{5}x

So, The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

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bekas [8.4K]

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6 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
PLZZZZZZZzzz help i dont get it
Anna71 [15]
4/5-3/7. First they need the same denominater: 4/5(7)=28/35, 3/7(5)=15/35. 28/35-15/35. Now subtract numerators: 28-15=13. So your answer H. 13/35 :)
6 0
3 years ago
Read 2 more answers
Solve for x: x/6 - 2 = 13
Mumz [18]
X=90
Hope this helps!
3 0
3 years ago
Y - 5 ='3/2(x+4) using that as a fraction write an equation in slope intercept form
frosja888 [35]
Y-5=3/2(x+4)
y-5= 3/2x +6
y=3/2x+11

Hope this helps :)
4 0
3 years ago
Read 2 more answers
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