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Ilia_Sergeevich [38]
3 years ago
6

(3-4 +5-3)-²help me​

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0

Answer:

Your answer is literally 1

Step-by-step explanation:

(3−4+5−3)2

=1*1

=1

Hope this is what your looking for

Luba_88 [7]3 years ago
6 0

Answer:

1

Step-by-step explanation:

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Can someone answer this plz (-2z^2-14)-(-12z^2)
Orlov [11]

Answer:

\large\boxed{(-2z^2-14)-(-12z^2)=10z^2-14}

Step-by-step explanation:

(-2z^2-14)-(-12z^2)=-2z^2-14+12z^2\qquad\text{combine like terms}\\\\=(-2z^2+12z^2)-14=10z^2-14

8 0
3 years ago
What's 1 plus 1. please help me ​
m_a_m_a [10]

Answer: 2

Step-by-step explanation:

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3 years ago
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You are drawing two cards, without replacement, from a standard deck of 52 cards. What is the
Serga [27]

Answer:

Dear student,

Answer to your query is provided below

Probability of drawing a 2 at first is (4/52) = (1/13)

Probability of drawing a face card in second try without replacement = 12/51

Step-by-step explanation:

Total no. Of cards = 52

Total no. Of cards of 2 = 4

Prob. Of drawing 2 = 4/52

Total no. Of face card = 12

Total no.of cards left in deck = 51

Prob. Of drawing face card = 12/51

5 0
3 years ago
Simplify <br> ‐19 ‐ 7( ‐17z + 13)<br> 4n ‐ 3( ‐9n + 13)
nataly862011 [7]

Answer:

for the first one it's 119z−110

the second one is 31n−39

i'm not sure if you wanted both together

so here just incase

31n+119z−149

Step-by-step explanation:

8 0
3 years ago
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Show how to use substitution or elimination to solve the following system of equations. Write the solution as an ordered pair.
max2010maxim [7]

Answer:

  (4, 6)

Step-by-step explanation:

<u>Substitution</u>

Using the second equation, we can substitute for y in the first equation.

  4x -(2x-2) = 10

  2x +2 = 10 . . . . simplify

  x +1 = 5 . . . . . . .divide by 2

  x = 4 . . . . . . . . . subtract 1

  y = 2(4) -2) = 6 . . . . substitute for x in the equation for y

The solution is (x, y) = (4, 6).

__

<u>Elimination</u>

Often, we like to start with both equations in standard form when we solve by elimination. That is nice, but not completely necessary.

We can eliminate the y-variable by simply adding the two given equations.

  (4x -y) +(y) = (10) +(2x -2)

  4x = 8 + 2x . . . . . collect terms. The y-variable has been eliminated.

  2x = 8 . . . . . . . . . subtract 2x

  x = 4 . . . . . . . . . . divide by 2

Y can be found using the second equation.

  (x, y) = (4, 6)

__

We could have eliminated the x-variable by multiplying the second equation by 2, then adding the two equations.

  (4x -y) +2(y) = (10) +2(2x -2)

  y = 6 . . . . . . . . . subtract 4x from both sides. The x-variable has been eliminated.

Now, x can be found using either equation.

  6 = 2x -2 . . . substitute for y in the second equation

  3 = x - 1 . . . divide by 2

  x = 4 . . . . . add 1

  (x, y) = (4, 6)

3 0
3 years ago
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