Answer:
The answer is the last one (32x^7y^15)
You can bring x to the second power (x^2) because (x) is basically x^1. This is a basic exponent rule. (x^m)^n = x^m times n.
Then you can apply this rule to (2xy^3)^5. First you bring two to the fifth power and get 32. Then you bring x^5 according to the rule. Then you bring y^15, also because of the rule.
Now you have:
x^2 times 32x^5y^15
Now you just multiply the like terms together (x^2 and x^5)
When you multiply two exponents with the same base, you add the exponents together: a^n times a^m = a^n+m.
So you end up with 32x^7y^15
Answer: (5+√2) and (3+√2)
Step-by-step explanation: Let (5+√2) and (3+√2) be two irrational numbers
Difference = (5+√2) - (3+√2)
Difference = 2
2 is a rational number
Answer:
(x-7) (x+4)
Step-by-step explanation:
x^2 - 3x - 28
What two numbers multiply to -28 and add to -3
-7*4 = -28
-7+4 = -3
(x-7) (x+4)
