Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Answer:
Let x represent the number from the sentence.
Step-by-step explanation:
2(x) + 2(1/x) = 20/3
2x + 2/x = 20/3
multiply both sides of the equation by 3x
6x + 6 = 20x
6x - 20x + 6 = 0
6x - 18x - 2x + 6 = 0
6x(x-3 -2(x-3) = 0
(6x-2 = 0 or x-3 = 0
6x = 2 or x = 3
x = 2/6
x = 1/3
Since x represented the number
Therefore x = 1/3 or 3
It is unchanged because the same number would still be in the middle and there would still be the same amount of numbers
if
11,15,21,22,23,27,30 before 22 is the median
if
11,15,21,22,23,27,30 after 22 is still the median
The median is unchanged
Answer:
-2.4
Step-by-step explanation:
maybe... i am 99.99% sure
B. The y-intercept is 0 so it can't be C or D and the slope is 5/1. How I remember this is rise/run. Hope this helps!