Ask question

Ask question

All categories

2 years ago

15

Kate wants to buy a new bicycle from a sporting goods store. The bicycle she wants normally sells for $490. The store has a sale

where all bicycles cost
6
7
of the regular price. What is the sale price of the bicycle?

1 answer:

o-na [289]2 years ago

6 0

Answer:

if you mean 6/7ths, then the answer is 420$

Step-by-step explanation:

You might be interested in

-7.66666, \sqrt(50,) -(157)/(20), -7.64 list these from least to greatest.

blagie [28]

Answer:

From least to greatest, the correct order is: $-\frac{157}{20}$ ; -7.666....; -7.64; and $\sqrt{50}$ .

Step-by-step explanation:

Since $\sqrt{50}$ is the only positive number, that means that it will be the greatest number on the list. $-\frac{157}{20}$ is equivalent to -7.85, which makes it the smallest number. So you can conclude that the correct order is $-\frac{157}{20}$ ; -7.666...; -7.64; and $\sqrt{50}$ .

4 0

3 years ago

If the length of the rectangle is twice the width and the perimeter of the rectangle is 30 cm what is the length and width of th

N76 [4]

Step-by-step explanation:

Hope it helps u

Plz Mark as brainlist

3 0

3 years ago

Read 2 more answers

a total of 35 students are going to a field trip to NASA'S Johnson space center in houston,texas if there needs to be one adult

Trava [24]

Answer:

at least 5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the answer if 202^2 base3 - 112^2 base3?

yuradex [85]

Answer:

Hello,

answer is 204 in base 10 or 21120 in base 3

Step-by-step explanation:

$((202)_3)^2=(202*202)_3=(112211)_3\\\\((112)_3)^2=(112*112)_3=(21021)_3\\\\(112211-21021)_3=(211120)_3=(204)_{10}\\\\\\\\\\Other\ way\\\\((202)_3)^2=((20)_{10})^2=(400)_{10}\\\\((112)_3)^2=((14)_{10})^2=(196)_{10}\\\\(400-196)_{10}=(204)_{10}=(21120)_3$

6 0

3 years ago

Find the 9th term geometric sequence 1,1/2,1/2^2

valentinak56 [21]

Answer: $t_9=\dfrac{1}{2^8}$

<u>Step-by-step explanation:</u>

$t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}$

3 0

3 years ago