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3 years ago

7

Cameron is creating a garden. He designs a rectangular garden with a length of (x+6) feet and a width of (x+2) feet. When x=5, w

hat is the area of the garden ?

1 answer:

Zolol [24]3 years ago

6 0

(5+6) multiplied by (5+2)
11 x 7
77
The area of the garden is 77 square feet.

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Last year Marta invested money in two accounts. The first account had an interest rate of 3% and the second account had an inter

KatRina [158]

The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.

<h3>How do we calculate the amount invested?</h3>

Let x represents the amount invested in the first account.

Therefore, we have:

Amount invested in the second account = x - 500

Interest income from first account = 3% * x = 0.03x

Interest income from second account = 5% * (x - 500) = 0.05x - 25

Total interest income = 0.03x + 0.05x - 25 = 719

Solving for x, we have:

0.08x = 719 + 25

x = 744 / 0.08

x = $9,300

Substituting for x, we have:

Amount invested in the second account = $9,300 - $500 = $8,800

Learn more about the amount invested here: brainly.com/question/24132106.

#SPJ1

3 0

2 years ago

Sushil rolls a fair dice 138 times. How many times would Sushil expect to roll an even number

dmitriy555 [2]

Since the chance of getting an even number on every roll is 3/6 or 1/2
We have to multiply 1/2 by 138

The answer is 69.

Hope this is correct, and pls correct me if I'm wrong :)

5 0

3 years ago

A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were

quester [9]

Answer:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

Step-by-step explanation:

For this case we have the following distribution given:

X 1 2 7

P(X) 1/5 2/5 2/5

We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

7 0

4 years ago

Please help worth a lot

KonstantinChe [14]

Answer:

(-2, -3)

Step-by-step explanation:

when its relected its just flipping over the horizontal axis (x-axis) so in turn that is the answer! :) hope this helped you

6 0

3 years ago

Bezzdna [24]

50 per share hope this helped

6 0

3 years ago