Answer:
The mass ratio of zinc to sulfide is 85:42.
2.5559 kg of Zn are in 3.82 kg of ZnS.
Explanation:
a) Mass of zinc sulfide = 254 g
Mass of zinc in a zinc sulfide sample = 170 g
Mass of sulfide in zinc sulfide sample = x
254 g = 170 g+ x
x = 84 g
The mass ratio of zinc to sulfide:
b) Mass of zincsulfide sample = 3.83 kg
The mass ratio of zinc to sulfide is 85:42.
Let the mass of zinc and sulfide be 85x and 42x respectively:
85 x+ 42 x=3.82 kg
x =0.03007 kg
Mass of an zinc= 85x=85 × 0.03007 kg= 2.5559 kg
The one with the highest pH would be a solution with 100 mL of water and also 20 mL of 0.1 M NaOH is added. Solutions without buffers would have the highest pH since the resistance to change is very low. Hope this answers the question.
Explanation:
mole of acid/mole of base=(concentration of acid×volume of acid)/(concentration of base×volume of base)
Na/Nb=CaVa/CbVb
1/2=(Ca×16.7)/(0.2×25)
0.2×25=2×Ca×16.7
Ca=(0.2×25)/(2×16.7)
Ca=0.15mol/dm³
mole of acid=Concentration×volume
mole of acid=0.15×(16.7/1000)
mole of acid=2.5×10^-3moles