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frez [133]
3 years ago
7

What type of change is a substance that changes form but remains the same?

Chemistry
1 answer:
Gelneren [198K]3 years ago
6 0
It is called a physical change. It is reversible and doesn't affect the chemical make-up.
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Please help me with these
padilas [110]
<span>The physical layers of the inner core and outer core form a single compositional layer.

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8 0
3 years ago
Consider the reaction, 2 d(g) + 3 e(g) + f(g) =&gt; 2 g(g) + h(g) when h is increasing at 0.64 mol/ls, how quickly is e decreasi
bekas [8.4K]
Answer is: 1,92 mol/L·s.
Chemical reaction: 2D(g) + 3E(g) + F(g) → <span>2G(g) + H(g). 
</span>H is increasing at 0,64 mol/L·<span>s.
From chemical reaction n(H) : n(E) = 1 : 3.
0,64 mol : n(E) = 1 : 3.
n(E) = 1,92 mol.
</span>E is decreasing at 1,92 mol/L·s.
8 0
3 years ago
if a lead can be extrated with 92.5% efficiency,what is the mass of ore required to make a lead sphere with 750%cm radius
Lady_Fox [76]
The mass of ore required is 21 700 t.

r = 750 cm

V = \frac{4}{3}  \pi  r^{3} = \frac{4}{3}  \pi  (750 cm)^{3} = 1.767 × 10⁹ cm³

The density of lead is 11.34 g/cm³.

So mass of lead sphere = 1.767 × 10⁹ cm³ × \frac{11.34 g}{1 cm^{3} } = 2.004 ×10¹⁰ g

2.004 ×10¹⁰ g × \frac{1 kg}{1000 g} = 2.004 × 10⁷ kg

2.004 × 10⁷ kg × \frac{1 t}{1000 kg} = 2.004 × 10⁴ t

92.5% efficiency means 92.5 t Pb per 100 t of ore.

Mass of ore = 2.004 × 10⁴ t Pb ×\frac{100 tore}{92.5 t Pb} = 2.17 × 10⁴ t ore = 21 700 t ore

6 0
3 years ago
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
3 years ago
Which property is shared by both acids and bases?
Evgen [1.6K]

\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}

3. Conducts electricity in aqueous solution.

  • Thanks
  • Hope it helps.
3 0
3 years ago
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