Question

If you obtained 2.50 moles of CuSO4 from the reaction of CuO and H2SO4, but the theoretical yield was 3.19 moles, what was the percent yield?

Answer 1

Answer:

• 78.4%

Explanation:

Just as context, write the chemical equation and the mole ratios

1) Balanced chemical equation:

• CuO (s) +  H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)

2) Therotetical (stoichiometric) mole ratios:

• 1 mol CuO : 1 mol  H₂SO₄  : 1 mol CuSO₄  : 1 mol H₂O

You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield

3) Percent yield

• Definition:

         Percent yield = (actual yield / theoretical yield)×100

• Theoretical yiedl (given): 3.19 moles CuSO₄

• Actual yield (given): 2.50 moles CuSO₄

• Calcualtion:

Substitute the values in the formula:

• Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%