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musickatia [10]
3 years ago
5

What is 2/3 x 5/6 x 14=

Mathematics
2 answers:
il63 [147K]3 years ago
7 0
I did it on the calculator and the answer is 7.77777777778

viva [34]3 years ago
3 0
7.777 and so on. Hope it helped :)
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Help me out please T-T​
Anettt [7]

Answer:

The simplyfied version would be 19/4

Show of work:

(1/4)^-2 = 4^2

3 × 8^2/3 × 1 = 12

(9/16)^1/2 = 3/4

4^2 - 12 + 3/4

Convert elements to fractions:

-12 × 4 + 3

---------- ----

4 4

Since the denominators are equal combine the fractions:

-12 × 4 + 3

---------------

4

-12 × 4 + 3 = -45

= -45/4

=4^2 - 45/4

4^2 = 16

16 - 45/4

16 × 4 - 45. 16 × 4 - 45

--------- ----- ----------------

4 4. 4

-> 16 × 4 - 45 = 19

= 19/4

7 0
3 years ago
Read 2 more answers
Solve for x<br> 1 − 6x ≤ − 17<br> please help i am crying rn
irina [24]

Answer:

x \geqslant 3

Step-by-step explanation:

subtract 1 from both sides

-6x<-17-1

simplify

-6x<-18

divide by 6 on both sides

x>3

4 0
3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
F(x)=x^2+1 and g(x)= [x-1]\sqrt{x}[/x-1] state the domain and find fog and​
weeeeeb [17]

Step-by-step explanation:

hi Maya how are you

I wasn't using this app so I didn't replied

and sorry for rejecting ur request in ff

I'll give my another I'd if u want to play

3 0
2 years ago
your friends says that an exterior angle can never be complementary to any of the interior angles in a triangle?
rusak2 [61]
Exterior angles are complementary to the opposite interior angle 

6 0
3 years ago
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