Answer:
interquartile range of original data:20
New data:15
Step-by-step explanation:
The original data is given as:
45 65 70 80 85 100.
lower quartile()=65
median of data()=(70+80)/2=75
upper quartile()=85
interquartile range=-
=85-65=20
The changed data is given as:
65 70 80 85
lower quartile()=(65+70)/2=67.5
median()=(70+80)/2=75
upper quartile()=(80+85)/2=82.5
interquartile range=-
=82.5-67.5=15.
There is no picture so I can't help.
Start by breaking the figure into simpler figures
Triangle 1
Triangle 2
Square
Then calculate the area for each one
Square: 2 cm times 2 cm = 4 cm
Triangle: 2 cm times 1 cm = 2 cm divided by 2 = 0.5 cm
Triangle: 2 cm times 1 cm = 2 cm divided by 2 = 0.5 cm
Add up all the values and get 5 cm squared
Answer:
C. Two-tailed paired t-test.
Step-by-step explanation:
Since Dr. Hernandez takes 30 samples from a contaminated lake and 30 fish from a pristine lake, he should use a two-tailed t-test.
Paired t-tests describe tests used to compare the means of two samples when each observation in one sample can be paired with an observation in the other sample. Dr. Hernandez can certainly pair the samples and observe the differences, so the answer is C. Two-tailed paired t-test.
Hope this helps!
The third term, fourth term and tenth term are -1, -3, -15 respectively.
<h3>
What is a sequence?</h3>
A sequence is a pattern of numbers in which successive terms differ by an constant term called the common difference or ratio.
Analysis:
For a sequence defined by the rule A(n) = 3 + (n-1)(-2)
Third term, n = 3
A(3) = 3 + (3-1)(-2) = -1
Fourth term, n = 4
A(4) = 3 + (4-1)(-2) = -3
Tenth term, n = 10
A(10) = 3 + (10-1)(-2) = -15
In conclusion, the third, fourth, tenth terms are -1, -3 and -15 respectively.
Learn more about sequence: brainly.com/question/6561461
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