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3 years ago

What is Index Law 3? please give explanation

2 answers:

8 0

The third and last law tells us that when we have to multiply a power in a bracket, by another power outside the bracket, we have to multiply the two powers together to get the answer.

rodikova [14]3 years ago

6 0

Answer:

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Step-by-step explanation:

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9x-8(x-6)=52 what is the answer

Effectus [21]

Answer:

x = 4

Step-by-step explanation:

Step 1: Write equation

9x - 8(x - 6) = 52

Step 2: Solve for x

Distribute -8: 9x - 8x + 48 = 52
Combine like terms: x + 48 = 52
Subtract 48 on both sides: x = 4

Step 3: Check

Plug in x to verify it's a solution.

9(4) - 8(4 - 6) = 52

36 - 8(-2) = 52

36 + 16 = 52

52 = 52

7 0

4 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$