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GarryVolchara [31]
2 years ago
11

What is Index Law 3? please give explanation

Mathematics
2 answers:
Anastaziya [24]2 years ago
8 0

The third and last law tells us that when we have to multiply a power in a bracket, by another power outside the bracket, we have to multiply the two powers together to get the answer.

rodikova [14]2 years ago
6 0

Answer:

hi hi hi hi hi

Step-by-step explanation:

plz follow me

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Ratio And Rates. Each ratio or rate needs to be a fraction in simples terms 1. 30 ft. To 60.Ft 2. 51 males to 21 females 3. 1,50
otez555 [7]

Given:

The ratio and rates:

1. 30 ft. To 60.Ft

2. 51 males to 21 females

3. 1,500 meters in 6 seconds

4. $36 for 4 rounds of shrimp

To find:

The fraction in simple terms for the given ratio and rates.

Solution:

1. 30 ft. To 60.Ft

\dfrac{30\text{ ft}}{60\text{ ft}}=\dfrac{1}{2}

2. 51 males to 21 females

\dfrac{51}{21}=\dfrac{17}{7}

3. 1,500 meters in 6 seconds

\dfrac{1500\text{ meters}}{6\text{ seconds}}=250\text{ meter/second}

4. $36 for 4 rounds of shrimp

\dfrac{\$ 36}{4}=\$ 9\text{ per round of shrimp}

4 0
3 years ago
Find an equivalent fraction 2/6= 2/5=
bulgar [2K]
2/6 = 1/3
2/5 = 4/10 

Hope this helps.
5 0
3 years ago
Read 2 more answers
Which fraction is not equivalent to 30/48 ?
laiz [17]
C and D.If I'm right,can u make me the brainliest answer?Thank You.
7 0
2 years ago
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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Decide if this statement is true or false.
AVprozaik [17]

Answer:

Step-by-step explanation:

I believe it’s false

7 0
2 years ago
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